Answer:
Devon needs add 60 mL of 5% acid solution and 30 mL of 20% acid solution
Explanation:
It know acid and water concentration for every solution. 2 equation are proposed because there are two unknowns. V1= volume 5%acid and V2 =volume 20% acid
<em>Acid </em>V1(0.05)+V2(0.2)=90mL(0.1)
<em>Water </em>V1(0.95)+V2(0.8)=90mL(0.9)
Clearing V1 from acid equation having to: V1=180-4V2
Replacing V1 in water equation having to: (180-4V2)(095)+V2(0.8)=81
Clearing V2 = 30mL
Replacing in water equation V1(0.05)+30(0.2)=9 So, V1=60mL
I hope it helps
Answer:
0.15 L
Explanation:
You need to first find the volume of the container. You can do this by dividing the mass by the density. This will give you the mass in mL.
5.00 kg = 5,000 g
(5,000 g)/(1.00 g/mL) = 5,000 mL
5,000 mL = 5 L
Now, find the volume the seawater will take up.
(5,000 g)(1.03 g/mL) = 4854.4 mL
4854.4 mL = 4.85 L
Subtract the two volumes to find the volume that left unfilled.
5 L - 4.85 L = 0.15 L
Answer:
C 1:1
Explanation:
Hydrogen loses an electron to becone +1 which is a cation and flourine gains that electron to have a full outer shell on the 2p subshell to become -1 and is an anion so the ratio is 1:1.
