Mixed Practice:

Chemistry

1 answer:

Afina-wow [57]3 years ago

5 0

Given

Mass of NO - 824 g

Molar mass of NO - 30.01g/mol

No of moles of NO = Given mass/Molar mass

No of moles of NO = 824/30.01= 27.45 mole

Hence 27.5 moles of NO are formed!

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MakcuM [25]

Answer:

Hydrogen is the excess reactant

Nitrogen is the limiting reactant

151.6g is theoretical yield

Explanation:

The reaction of N₂ with H₂ to produce NH₃ is:

N₂ + 3H₂ → 2NH₃

To find theoretical yield we need to determine limiting reactant with the moles of each gas as follows:

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Hydrogen -Molar mass: 2g/mol-

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For a complete reaction of 4.46 moles of N2 there are needed:

4.46 moles N2 * (3moles H2 / 1mol N2) = 13.38 moles of hydrogen

As there are 62.5 moles of hydrogen:

<h3>Hydrogen is the excess reactant</h3><h3>Nitrogen is the limiting reactant</h3><h3 />

With nitrogen, the limiting reactant, we determine theoretical moles (Assuming 100% of the reaction occurs) and theoretical yield (In mass):

4.46 moles N2 * (2moles NH3 / 1mol N2) = 8.92 moles of ammonia

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8.92 moles of ammonia * (17g/mol) =

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Answer:

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