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irinina [24]
4 years ago
12

What element has a total of 3 p-sublevel electrons?

Chemistry
2 answers:
gogolik [260]4 years ago
7 0

N, P, As, Sb, and Bi

Crank4 years ago
6 0

Elements with three p-electrons....


That would be N, P, As, Sb, and Bi -- elements in group 15


For example, energy diagram showing "empty" orbitals up through the 3p.

.....3p __ __ __

3s __

.....2p __ __ __

2s __

1s __


Energy diagram of phosphorous showing three unpaired electrons in 3p-sublevel

.....3p ↑_ ↑_ ↑_

3s ↑↓

.....2p ↑↓ ↑↓ ↑↓

2s ↑↓

1s ↑↓


According to Hund's rule, the electrons singly occupy the p-orbitals, and all have the same spin.

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Does a part or slice of a substance have a different density than the whole piece?<br><br> Pls help!
Nostrana [21]
Density is defined as mass per unit volume so even when you cut an object in half unit volume does not change so each part would have a different density even if it’s cut into the same pieces
3 0
3 years ago
Hydrogen sulfide gas reacts with oxygen to produce sulfur dioxide gas and water according to the balance equation:
ser-zykov [4K]

2 mol of H2S react with 3 mol of O2

5.6 mol of H2S react with =5.6×3/2=8.4 mol of O2

5 0
3 years ago
If the forward reaction is favored in the equilibrium, what will increase?
Lorico [155]

Answer:

Option C:- concentration of products

Explanation:

According to Le Chateleir's principle,

if the forward reaction is favored in the equilibrium then concentration of products will increase and concentration of reactants will decrease.

If the reverse reaction is favored in the equilibrium then concentration of products will decrease and concentration of reactants will increase.

5 0
4 years ago
Compute the atomic density (the number of atoms per cm3 ... rather than the mass density g/cm3) for a perfect crystal of silicon
serious [3.7K]

Answer:

        \large\boxed{\large\boxed{5.00\times 10^{22}atoms/cm^3}}

Explanation:

You can convert the <em>density</em> into <em>atomic density</em> using the <em>atomic weight </em>and Avogadro's number

A dimensional analysis is very helpful:

           \dfrac{g}{cm^3}\times \dfrac{mol}{g}\times \dfrac{atoms}{mol}=\dfrac{atoms}{cm^3}

Follow the chain: g cancels with g, mol cancels with mol; at the end, what remains is atoms/cm³, which is what you want.

Use that with your data:

         \dfrac{2.33g}{cm^3}\times \dfrac{1mol}{28.09g}\times \dfrac{6.022\times 10^{23}atoms}{mol}=\approx 5.00\times10^{22}atoms/cm^3

3 0
3 years ago
What is the molar mass of 4.23 g of an elemental gas in a 2.5L container at 282K and 1.4 atm?
balu736 [363]

Answer:

27.98g/mol

Explanation:

Using ideal gas law equation;

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

T = temperature (K)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

According to the information given:

V = 2.5L

P = 1.4 atm

T = 282K

n = ?

Using PV = nRT

n = PV/RT

n = 1.4 × 2.5/0.0821 × 282

n = 3.5/23.1522

n = 0.151mol

Using the formula to calculate molar mass of the elemental gas:

mole = mass/molar mass

Molar mass = mass/mole

Molar mass = 4.23g ÷ 0.151mol

Molar mass = 27.98g/mol

6 0
3 years ago
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