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3 years ago

Difference between cold process soap making and hot process soap making

Chemistry

1 answer:

stepladder [879]3 years ago

7 0

Answer:

Unlike cold process soap, the essential oils or fragrance/additives are added after gel phase. ... Cold process soap heats from the inside out, while hot process soap heats from the outside in. Unlike cold process soap, that lasts for 4-6 weeks, hot process soap can be used immediately after it hardens.

Explanation:

hope it helps you

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Be sure to answer all parts. A person drinks four glasses of cold water (3.2 degree C) every day. The volume of each glass is 2.

Lelechka [254]

Explanation:

(a). The given data is as follows.

Volume of one glass of water = $2.2 \times 10^{2}$ ml = 220 ml

Volume of 4 glass of water = $220 \times 4$ = 880 ml

We known that density of water is 1 g/ml. Therefore, calculate the mass of water as follows.

Mass of water = $880 ml \times 1 g/ml$

= 880 gm

= 0.88 Kg (as 1 kg = 1000 g)

The relation between heat energy, mass and temperature change is as follows.

Q = $mC \Delta T$

$\Delta T = (37 - 3.2)^{o}C = 33.8^{o}C$

Putting the given values into the above formula as follows.

Q = $mC \Delta T$

= $0.88 \times 4.186 J/g^{o}C \times 33.8^{o}C$

= 124.5 kJ

Hence, the body have to supply 124.5 kJ to raise the temperature of the water to 37 degree C.

(b). As we know that the heat of fusion of ice is 333 J/g.

So, energy required for $8.4 \times 10^{2}$ g or 840 g is as follows.

$333 \times 840$ = 279.72 kJ

Heat capacity of water= 4.184 $J/g^{o}C$

Now, heat energy will be as follows.

Q = $4.184 \times 840 g \times 37^{o}C$

= 130.03 kJ

Therefore, total heat required = (279.72 + 130.03) kJ

= 409.75 kJ

Hence, for the given situation your body should lose 409.75 kJ of heat.

6 0

3 years ago

Find and fix each mistake in the following equilibrium constant expressions.

IRINA_888 [86]

Answer:

A. c. Keq=[H2]^2[S2]/[H2S]^2

B. b. Keq=[COCl2]/[CO][Cl2]

Explanation:

Hello,

In this case, considering the law of mass action which states that the equilibrium expression is written in terms of the concentration of products divided by the concentration of reactants considering the stoichiometric coefficients as powers we obtain:

A. For the reaction:

$2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)$

The equilibrium expression is:

$Keq=\frac{[H_2]^2[S_2]}{[H_2S]^2}$

Therefore, answer is c. Keq=[H2]^2[S2]/[H2S]^2.

B. For the reaction:

$CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)$

The equilibrium expression is:

$Keq=\frac{[COCl_2]}{[CO][Cl_2]}$

Therefore, answer is b. Keq=[COCl2]/[CO][Cl2].

Regards.

8 0

3 years ago

Hydrogen reacts with 0.771 g of carbon to form 0.90 g of a compound. What is the mass percent of hydrogen in the compound

morpeh [17]

Answer: 14.3%

Explanation: In order to find the mass percent of hydrogen in this compound, you must determine how many grams of hydrogen you'd get in 100 g of compound.

In your case, you know that an unknown mass of hydrogen reacts with 0.771 g of carbon to form 0.90 g of hydrocarbon, which is a compound that contains only carbon and hydrogen.

Use the total mass of the hydrocarbon to determine how many grams of hydrogen reacted with the carbon.

Now, if 0.90 g of this compound contain 0.129 g of hydrogen, it follows that 100 g of this compound will contain.

So, if 100 g of this compound contain 14.33 g of hydrogen, it follows that the mass percent of hydrogen is 14.3%

4 0

4 years ago

Read 2 more answers

ANSWER FAST PLZ!!!!!!!!!!!!!!

kondor19780726 [428]

Answer: water should be recycled

Explanation:

3 0

4 years ago

A chemist mixes 75.0 g of an unknown substance at 96.5°C with 1,150 g of water at 25.0°C. If the final temperature of the system

AleksAgata [21]

To do this problem it is necessary to take into account that the heat given by the unknown substance is equal to the heat absorbed by the water, but considering the correct sign:

$-m\cdot c_e\cdot \Delta T = m_w\cdot c_e_w\cdot \Delta T_w$

Clearing the specific heat of the unknown substance:

$c_e = \frac{m_w\cdot c_e_w\cdot \Delta T_w}{m\cdot \Delta T} = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot (37.1 - 25.0)^\circ C}{75\ g\cdot (37.1 - 96.5)^\circ C}$

$c_e = -\frac{1\ 150\ g\cdot 4.184\frac{J}{g\cdot ^\circ C}\cdot 12.1^\circ C}{75\ g\cdot (-59.4)^\circ C} = \bf 13.07\frac{J}{g\cdot ^\circ C}$

6 0

3 years ago

Difference between cold process soap making and hot process soap making​

Difference between cold process soap making and hot process soap making