Question

How many factors in the expression 8(x + 4)(y + 4)(z² + 4z + 7) have two terms?

Answer 1

Answer:

There are 2 Factors which has 2 terms.

Step-by-step explanation:

Given: Expression = $8(x+4)(y+4)(z^2+4z+7)$

To find: No. of factors with 2 terms

It's clear, Given expression can not be further factorized.

So, we have 4 factors in it.

Factor 1 :

8

it has 1 term.i.e., 8 itself.

Factor 2:

x + 4

It has 2 terms .i.e., x & 4

Factor 3:

y + 4

It has 2 terms.i.e., y & 4

Factor 4:

$z^2+4z+7$

It has 3 terms.i.e., $z^2$, 4x & 7

Therefore, There are 2 Factors which has 2 terms.

Answer 2

The answer is 2 factors.

There are four factors:
8                       - 1 term (8)
(x + 4)               - 2 terms (x and 4)
(y + 4)               - 2 terms (y and 4)
(z² + 4z + 7)      - 3 terms (z, 4z, and 7)