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Brilliant_brown [7]
4 years ago
11

What is speed?

Physics
2 answers:
RoseWind [281]4 years ago
4 0
Distance per time is the answer
Shalnov [3]4 years ago
3 0
Speed is distance over time.... so the 2nd one miles per hour
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What type of fault usually occurs because of compression?
Kamila [148]
The answer is:
<span>Reverse</span>
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3 years ago
the force that is exerted when a shopping cart is pushed. the forces that causes a metal ball to move toward a magnet
alexandr402 [8]

Answer:

The force that is exerted when a shopping cart is pushed is a type of push force, supplied by the muscles of the cart pusher's body.

The forces that causes a metal ball to move toward a magnet is a type of pull force that is as a result of the magnetic field forces.

Explanation:

Forces are divided into push forces that tends to accelerate a body away from the source of the force, and pull forces that accelerates the body towards the force source.

Examples of push forces includes pushing a cart, pushing a table, repulsion of two similar poles of a magnet etc. Examples of pull forces includes a attractive force between two dissimilar poles of a magnet, pulling a load by a rope, a dog pulling on a leash etc.

8 0
3 years ago
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Irina-Kira [14]
All electromagnetic waves travel in vacuum (space) at the speed of light (3 * 10^8 m/s). Radio waves is just a member of the electromagnetic spectrum. All electromagnetic waves follow the wave equation: speed = frequency * wavelength. With all electromagnetic waves, the speed in space is the same.
6 0
3 years ago
Help! series circuit practice, I'm not sure what formula to use.
notka56 [123]

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5 0
3 years ago
A golf club exerts an average horizontal force of 1005 N in the –x direction on a 453 grams golf ball that is initially at rest
adelina 88 [10]

Answer:

The impulse is 1.89 Ns and final velocity of the golf 4.17 \frac{m}{s}

Explanation:

Given:

Average force F = 1005 N

Contact time t = 1.89 \times 10^{-3} sec

Mass of golf ball m = 453 = 0.453 kg

(a)

Impulse is given by,

   J = Ft

   J = 1005 \times 1.89 \times 10^{-3}

   J  = 1.89 Ns

(b)

For finding the final velocity,

  J = \Delta P

  J = mv

1.89 = 0.453 v

  v = 4.17 \frac{m}{s}

Therefore, the impulse is 1.89 Ns and final velocity of the golf 4.17 \frac{m}{s}

7 0
3 years ago
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