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Paladinen [302]
3 years ago
11

Predict what you need to do do to use boyle’s law on a macroscopic scale

Chemistry
1 answer:
Verizon [17]3 years ago
4 0

Answer:

Explanation:

Boyle's law states that:

"For an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume".

Mathematically:

pV=const.

where

p is the pressure of the gas

V is the volume of the gas

The important condition in order to verify Boyle's law in an experiment is that the temperature of the gas must remain constant. This means that the temperature of the gas during the experiment must be kept constant. This can be achieved, for example, by placing the apparatus containing your gas (for example, a glass tube) inside a thermal bath: for instance, a large amount of water kept at constant temperature. This way, the gas inside the tube will also have the same temperature of the water, which is constant.

Learn more about ideal gases:

brainly.com/question/9321544

brainly.com/question/7316997

brainly.com/question/3658563

#LearnwithBrainly

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Sulfuric acid is essential to dozens of important industries from steelmaking to plastics and pharmaceuticals. More sulfuric aci
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Given:

K = 0.71 = Kp

The reaction of sulphur with oxygen is

                            S(s)   + O2(g)  ---> SO2(g)

initial Pressure                   6.90         0

Change                                -x            +x

Equilibrium                     6.90-x          x

Kp = pSO2 / pO2 = 0.71 = x / (6.90-x)

4.899 - 0.71x  = x

4.899 = 1.71x

x = 2.86 atm = pressure of SO2 formed

temperature = 950 C = 950 + 273.15 K = 1223.15 K

Volume = 50 L

Let us calculate moles of SO2 formed using ideal gas equation as

PV = nRT

R = gas constant = 0.0821 L atm / mol K

putting other values

n = PV / RT = 2.86 X 50 / 1223.15 X 0.0821 = 1.42 moles

Moles of Sulphur required = 1.42 moles

Mass of sulphur required or consumed = moles X atomic mass of sulphur

mass of S = 1.42 X 32 = 45.57 grams or 0.04557 Kg  of sulphur



 


6 0
3 years ago
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Leokris [45]

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