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Paladinen [302]
3 years ago
11

Predict what you need to do do to use boyle’s law on a macroscopic scale

Chemistry
1 answer:
Verizon [17]3 years ago
4 0

Answer:

Explanation:

Boyle's law states that:

"For an ideal gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume".

Mathematically:

pV=const.

where

p is the pressure of the gas

V is the volume of the gas

The important condition in order to verify Boyle's law in an experiment is that the temperature of the gas must remain constant. This means that the temperature of the gas during the experiment must be kept constant. This can be achieved, for example, by placing the apparatus containing your gas (for example, a glass tube) inside a thermal bath: for instance, a large amount of water kept at constant temperature. This way, the gas inside the tube will also have the same temperature of the water, which is constant.

Learn more about ideal gases:

brainly.com/question/9321544

brainly.com/question/7316997

brainly.com/question/3658563

#LearnwithBrainly

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ANSWER
B.

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7 0
1 year ago
Convert 27.7 kilometers to centimeters.
Stolb23 [73]

Answer:

The correct answer is - 2770000 cm.

Explanation:

1 kilometer = 1000 meter

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1 kilometer = 100*1000 cm

1 km = 100000 cm.

then,

27.7 kilometers = 2.77 × 10^6 centimeters

So, 27.7 kilometers = 27.7 × 100000

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7 0
2 years ago
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6 0
3 years ago
An acid is any substance that
ehidna [41]

Answer:

C

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4 0
2 years ago
Wind : swirls :: chemical bond : ___________.
drek231 [11]
Options are as follow,

1)  Flashes
2)  Skips
3)  Stretches
<span>4)  Jumps
</span>
Answer:
            Option-3 (stretches) is the correct answer.

Explanation:
                    The best analogy which suits a chemical bond is the stretching of chemical bonds. Remaining verbs doesn't explain the property of chemical bond. For example, the chemical bonds did not flashes, neither they skip or jump.
                    The chemical bonds can stretch and bend. As predicted from IR spectroscopy, different bonds can stretch and bend at different energies. The stretching of bonds require more energy while, bending of bonds require less energy.
4 0
3 years ago
Read 2 more answers
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