1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gnoma [55]
3 years ago
13

At 900∘c titanium tetrachloride vapor reacts with molten magnesium metal to form solid titanium metal and molten magnesium chlor

ide. what is being oxidized, and what is being reduced?
Chemistry
2 answers:
german3 years ago
7 0
TiCl4 is being reduced and Mg being oxidized
liberstina [14]3 years ago
5 0

Answer:

Magnesium is being oxidized.

Titanium is being reduced.

Explanation:

Hello,

The undergoing chemical reaction is:

TiCl_4+2Mg-->Ti+2MgCl_2

Next, oxidation states are assigned:

Ti^{+4}Cl^-_4+2Mg^0-->Ti^0+2Mg^{+2}Cl^{-}_2

Half reactions are as follows:

Ti^{+4}+4e^--->Ti^0\\Mg^0-->Mg^{+2}+2e^-

Finally, as the magnesium increases its oxidation state, it is being oxidized and as the titanium decreases its oxidation state it is being reduced.

Best regards.

You might be interested in
Which compound can act as both a Bronsted-Lowry acid and a Bronsted-Lowry base?
Dvinal [7]
The answer is A. Water

Bronsted-Lowry base compounds are those that can accept protons

Bronsted-Lowry Acid Compounds are those that can recieve one

Water / H2O is an Amphoteric compund which mean that its molecul can act as a Base and Acid compound, so the answer is A.
5 0
3 years ago
A Silty Clay (CL) sample was extruded from a 6-inch long tube with a diameter of 2.83 inches and weighed 1.71 lbs. (a) Calculate
inna [77]

Answer:

a) the wet density of the CL sample is 0.0453 lb/in³

b) the water content in the sample is 65.37%

c) the dry density of the CL sample is 0.0274 lb/in³

Explanation:

Given that;

diameter d = 2.83 in

length L = 6 in

weight m = 1.71 lbs

A piece of clay sample had wet-weight of 140.9 grams  and dry-weight of 85.2 grams

a) wet density of the CL sample

wet density can be expressed as  p = M /v

V is volume of sample which is; π/4×d²×L

so p = M / π/4×d²×L

we substitute

p = 1.71 / (π/4 × (2.83)²× 6

p = 1.71 / 37.741

p = 0.0453 lbs/in³

so the wet density of the CL sample is 0.0453 lb/in³

b)

water content of sample is taken as;

w =  (wet_weight - dry_weight) / dry_weight

we substitute

w = (140.9 - 85.2) / 85.2

w = 55.7 / 85.2

w = 0.6537 = 65.37%

therefore the water content in the sample is 65.37%

c)

dry density of the CL sample

to determine the dry density, we say;

Sd = p / ( 1 + w )

we substitute

Sd = 0.0453 / ( 1 + 0.6537)

Sd = 0.0453 /  1.6537

Sd = 0.0274 lb/in³

therefore the dry density of the CL sample is 0.0274 lb/in³

8 0
3 years ago
As a chemical reaction occurs, the thermometer in the container records a drop in temperature. What is true of the reaction?
nadya68 [22]
<span>When a chemical reaction occurs and the thermometer in the container records a drop in temperature t</span>he reaction is exothermic because heat was released by the reaction.

 <span>B. The reaction is exothermic because heat was released by the reaction. is your answer.

Hoped I helped!</span>
4 0
3 years ago
Read 2 more answers
How many moles of ScCl3 can be produced when 10.00 mol Sc react with 9.00 mol Cl2
Nuetrik [128]

Answer:

Moles of ScCl_3 = 6 moles

Explanation:

The reaction of Sc and Cl_2 to make ScCl_3 is:

2Sc+3Cl_2⇒2ScCl_3

The above reaction shows that 2 moles of Sc  can react with 3 moles of Cl_2 to form ScCl_3.

Mole Ratio= 2:3

For 10 moles of Sc we need:

Moles of Cl_2 = Moles of Sc *\frac{3 moles of Cl_2}{2 Moles of Sc}

Moles of Cl_2 = 10 *\frac{3 moles of Cl_2}{2 Moles of Sc}

Moles of Cl_2 =15 moles

So 15 moles of Cl_2 are required to react with 10 moles of Sc but we have 9 moles of Cl_2 , it means Cl_2 is limiting reactant.

Moles of ScCl_3=Given\  Moles\  of\ Cl_2 *\frac{2\  Moles\ o\ fScCl_3}{3\ Moles\ of\ Cl_2}

Moles\ of\  ScCl_3=9 *\frac{2\  Moles\ of\ ScCl_3}{3\ Moles\ of\ Cl_2}

Moles of ScCl_3= 6 moles

4 0
3 years ago
Read 2 more answers
H2, N2, O2 molecules. . . A)must be polar. must be nonpolar. . B)can be polar or nonpolar depending on geometric . C)configurati
LenKa [72]

Answer: The correct option is A.

Explanation: The given molecules are the molecules of same element.

These molecules are considered as diatomic species.

Polar molecules are the molecules in which some polarity is present in the bond. These molecules are formed when there is some difference in the electronegativities of the elements. Example: HCl

Non-polar molecules are the molecules where no polarity is present in the bond. These molecules are formed when there is no difference in the electronegativities of the elements. Example: H_2, O_2

The given molecules are non-polar in nature.

Hence, these molecules must be non-polar. So, the correct option is A.

6 0
3 years ago
Read 2 more answers
Other questions:
  • Which of the following is false regarding supersonic speed?
    10·1 answer
  • For an atom’s electrons, how many energy sublevels are present in the principal energy level n = 4? 4 9 10 16 32
    10·2 answers
  • A 2.00 L container of nitrogen has a pressure of 3.2 atm. What volume would the container be at if the pressure decreased to 1.0
    13·1 answer
  • Watson and Crick worked out the structure of DNA molecules in 1952. This discovery affected the legal system that is used in soc
    5·2 answers
  • Putting rock salt on the roads during a snowstorm is an example of
    9·2 answers
  • Which is always the first step in dealing with an accident in the lab?
    5·2 answers
  • Consider the molecule SiCl4. The electronegativity values for Si and Cl are 1.8 and 3.0, respectively. Based on these values and
    6·2 answers
  • How does the brain receive information from the light entering the eye?
    13·1 answer
  • I need help please. The top question.
    13·1 answer
  • What has more particles: a mole of hydrogen or a mole of uranium?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!