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otez555 [7]
2 years ago
9

How many moles are in 4.3 x 1024 molecules of H20?

Chemistry
1 answer:
Bond [772]2 years ago
4 0

Answer:

\boxed {\boxed {\sf About 7.1 \ mol \ H_2O}}

Explanation:

To convert from molecules to moles, we must use Avogadro's Number: 6.022*10²³. This tells us the amount of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, the particles are molecules of water.

\frac {6.022*10^{23} \ molecules \ H_2O} {1 \ mol \ H_2O}

Multiply by the given number of molecules.

4.3 *10^{24} \ molecules \ H_2O *\frac {6.022*10^{23} \ molecules \ H_2O} {1 \ mol \ H_2O}

Flip the fraction so the molecules of water cancel.

4.3 *10^{24} \ molecules \ H_2O *\frac {1 \ mol \ H_2O} {6.022*10^{23} \ molecules \ H_2O}

4.3 *10^{24}  *\frac {1 \ mol \ H_2O} {6.022*10^{23} }

\frac {4.3 *10^{24}\ mol \ H_2O} {6.022*10^{23} }

7.140484889 \ mol \ H_2O

The original measurement of atoms has 2 significant figures ( 4 and 3), so our answer must have the same. For the moles we calculated, that is the tenth place. The 4 in the hundredth place tells us to leave the 1.

7.1 \ mol \ H_2O

There are about 7.1 moles of water.

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Copper(I) compounds in aqueous solutions are unstable and disproportionate:
Cu₂SO₄ = Cu + CuSO₄
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v=0.250 L

n(Cu₂SO₄)=m(Cu₂SO₄)/M(Cu₂SO₄)

c=n(Cu₂SO₄)/v=m(Cu₂SO₄)/(vM(Cu₂SO₄))

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Be sure to answer all parts. Write the equations representing the following processes. In each case, be sure to indicate the phy
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Answer:

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4.O^{2-}(g) \rightarrow O^{-}(g)+e^{-}

Explanation:

1.

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The electron affinity of S^{-} is as follows.

S^{-}(g)+e^{-} \rightarrow S^{2-}(g)

2.

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3.

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Hence, it does not require more electrons to get stability.

Therefore,the electron affinity of  Mg^{2+} is zero.

4.

The ionization energy of O^{2-} is follows.

O^{2-}(g) \rightarrow O^{-}(g)+e^{-}

3 0
3 years ago
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