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Artemon [7]
3 years ago
5

An element from group 2 will form ionic bonds with

Physics
1 answer:
Harlamova29_29 [7]3 years ago
5 0

Any non- metal group 13-17

Explanation:

An element from group 2 will form ionic bonds with any non - metal group 13 - 17.

An ionic bond usually forms between metals and non-metals.

  • In the main group on the periodic table, metals occupy the first two groups.
  • Ionic bonds are formed between two atoms with large electronegativity differences.
  • These are simply metals and non-metals.
  • The bond forms when metals donates their valence electrons to the non-metals.

Learn more:

Ionic bond brainly.com/question/10826758

#learnwithBrainly

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Is a cinder cone volcanoe constructive or deconstructive
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Cinder cone volcanoes can be associated with either constructive or destructive margins.<span>
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A constant power is supplied to a rotating disc .the relationship of angular velocity of disc and number of rotations made by th
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A rotating disc supplied with constant power where the relationship of the angular velocity of the disc and the number of rotations made by the disc is governed by Newton's second law for rotation. This law is specially made for rotating bodies which is extracted from Newton's second law of motion. 
6 0
3 years ago
Will give correct answer brainliest<br><br>5 kg m/s<br>8kg m/s<br>80 kg m/s<br>200 kg m/s​
o-na [289]

Answer: Here this will help you..

Explanation:

1 kg-m/s to kilogram-force meter/second = 1 kilogram-force meter/second

5 kg-m/s to kilogram-force meter/second = 5 kilogram-force meter/second

10 kg-m/s to kilogram-force meter/second = 10 kilogram-force meter/second

20 kg-m/s to kilogram-force meter/second = 20 kilogram-force meter/second

30 kg-m/s to kilogram-force meter/second = 30 kilogram-force meter/second

40 kg-m/s to kilogram-force meter/second = 40 kilogram-force meter/second

50 kg-m/s to kilogram-force meter/second = 50 kilogram-force meter/second

75 kg-m/s to kilogram-force meter/second = 75 kilogram-force meter/second

100 kg-m/s to kilogram-force meter/second = 100 kilogram-force meter/second

8 0
2 years ago
A jetliner has a velocity of 95 m/s. What is the displacement of the jetliner at t=3.0 seconds?
charle [14.2K]
Distance = speed / time

speed = 95 m/s
time = 3 s

distance = 95 / 3 m

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5 0
3 years ago
ILI
Nikolay [14]

The original kinetic energy will be 0 J and the final kinetic energy will be 7500 J and the amount of work utilized will be similar to the final kinetic energy i.e., 7500 J.

<u>Explanation:</u>

As it is known that the kinetic energy is defined as the energy exhibited by the moving objects. So the kinetic energy is equal to the product of mass and square of the velocity attained by the car. Thus,

                  \text {Kinetic energy}=\frac{1}{2} m v^{2}

So the initial kinetic energy will be the energy exerted by the car at the initial state when the initial velocity is zero. Thus the initial kinetic energy will be zero.  

The final kinetic energy is

\text {Kinetic energy}=\frac{1}{2} m v^{2}=\frac{1}{2} \times 600 \times 5 \times 5 = 7500 J

As the work done is the energy required to start the car from zero velocity to 5 m/s velocity.  

                       Work done = Final Kinetic energy - Initial Kinetic energy

Thus the work utilized for moving the car is  

                         Work done = 7500 J - 0 J = 7500 J

Thus, the initial kinetic energy of the car is zero, the final kinetic energy is 7500 J and the work utilized by the car is also 7500 J.

7 0
3 years ago
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