A ball with an initial velocity of 12 m/s is rolling up a hill. The ball accelerates at a rate of -2.6 m/s/s.
1 answer:
You might be interested in
Answer:
Therefore,
The frequency heard by the engineer on train 1
Explanation:
Given:
Two trains on separate tracks move toward each other
For Train 1 Velocity of the observer,
For Train 2 Velocity of the Source,
Frequency of Source,
To Find:
Frequency of Observer,
(frequency heard by the engineer on train 1)
Solution:
Here we can use the Doppler effect equation to calculate both the velocity of the source and observer
, the original frequency of the sound waves
and the observed frequency of the sound waves
,
The Equation is
Where,
v = velocity of sound in air = 343 m/s
Substituting the values we get
Therefore,
The frequency heard by the engineer on train 1
Answer:
r = 3519.55 m
Explanation:
We know that the acceleration of a particle in a circular motion is directed towards the center of the circumference and has magnitude:
F = rω^2
Where r is the radius of the circumference and ω is the angular velocity.
From the two acceleration vectors we find that their magnitude is
√(7^2+6^2) = √85
Therefore:
√85 m/s^2= rω^2
Now we need to calculate the angular velocity to obtain the radius. Since t2-t1 = 3s is less than one period we can be sure that the angular velocity is equals to the angle traveled between this time divided by 3 s.
The angle with respect to the x-axis for the particle at t1 and t2 is:
Therefore, the angular velocity ω is (in radians per second):
Therefore:
r = √85 / (0.0511813)^2 = 3519.55 m