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3 years ago

Explain whether a monopolist uses recources efficiently

1 answer:

7 0

It depends on the monopolist, it's in their best interest to use resource efficiently though because it can result in more profit naturally

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Hardness is indirectly related to: specific gravity surface roughness strength of chemical bonds weight

Zepler [3.9K]

The strength of chemical bonds would be the best answer to this question. Hardness is indirectly related to the strength of chemical bonds. Hardness is the resistance from the destruction of an object itself from a material. Hardness does not need to strength of chemical bonds in order to have this resistance.

5 0

3 years ago

Read 2 more answers

If the spring constant k of a pogo stick is 3500 N m and the weight of the person on the pogo stick is 700 N, how much is the sp

algol [13]

As we know that spring force is given by

$F = kx$

here we know that

F = 700 N

also we know that

k = 3500 N/m

now from above equation we will have

$700 = 3500 (x)$

now we will have

$x = \frac{700}{3500}$

$x = \frac{1}{5} m = 20 cm$

so here we can say that end of the spring will be compressed by 20 cm

6 0

3 years ago

What is laser Optics, and where is it used?

alexdok [17]

Answer: Laser optics is an laser instrumentation that is used to material processing which uses also coatings,substrates,and of different wavelengths of a superior performance

Explanation:

3 0

4 years ago

8-14 A Cu-30% Zn alloy tensile bar has a strain-hardening coefficient of 0.50. The bar, which has an initial diameter of 1 cm an

77julia77 [94]

Answer:

The true stress at true strain 0.05cm/cm is 80MPa

Explanation:

Given that

the strength coefficient is K

true strain is ε

strain hardening exponent is n

initial diameter of bar is d = 1cm, (10mm)

tensile force is F

engineering stress(S) = 120

the engineering stress(S) = $\frac{F}{\frac{\pi }{4}(d^2) }$

To find force (F) =

120 = $\frac{F}{\frac{\pi }{4}(100^{2} )}$

F = 120 * (π/4) * (100)

F = 9425N

Calculate the true strain (ε) = In (l₀ / l₁)

where

l₀ = initial length of the metallic bar = 3cm

l₁ = final length of metallic bar = 3.5cm

ε = In (3.5 / 3)

= In 1.1667

= 0.154cm/cm

Calculate the true stress (σ) at fracture point

= $\frac{F}{\frac{\pi }{4}(d^2) }}$

tensile force is F and final diameter of bar is d₁ (d in the eqn)

Substitute 9425 N for F and 0.926 cm (9.26mm) for d₁ (d in the eqn)

σ = $\frac{9425}{\frac{\pi }{4}(9.26^2) }}$

= 140MPa

To find the strength coefficient (K) of the material bar

K = $\frac{140}{\sqrt{0.154} }$

K = $\frac{140}{0.3925}$

= 356.75MPa

To calculate the true stress σ true strain of 0.05cm/cm

K = 356.75MPa

σ = $356.75(0.05)^0^.^5$

= $356.75 ( 0.2236)$

= 80MPa

The true stress at true strain 0.05cm/cm is 80MPa

6 0

3 years ago

A straight wire carries a current of 238 mA from right to left. What is the magnetic field at a point 10.0 cm directly below the

Alex777 [14]

Answer:

B = (4.76 × 10⁻⁷) T

Explanation:

From Biot Savart's law, the magnetic field formula is given as

B = (μ₀I)/(2πr)

B = magnetic field = ?

I = current = 238 mA = 0.238 A

μ₀ = magnetic constant = (4π × 10⁻⁷) H/m

r = 10 cm = 0.1 m

B = [4π × 10⁻⁷ × 0.238)/(2π×0.1)]

B = (4.76 × 10⁻⁷) T

The direction of the magnetic field is in the clockwise direction wrapped around the current-carrying wire.

Hope this Helps!!!

4 0

3 years ago