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3 years ago

Which of the following reactions could be used to power a battery because of the transfer of electrons?

Chemistry

1 answer:

Trava [24]3 years ago

3 0

Answer is: Zn + Cu2+ → Zn2+ + Cu.

In this chemical reaction, there is transfer of electrons from zinc (Zn) to copper (Cu). Zinc change oxidation number from 0 to +2 (lost electrons) and copper change oxidation number from +2 to 0 (gain electrons).

Oxidation half reaction: Zn⁰ → Zn²⁺ + 2e⁻.

Reduction half reaction: Cu²⁺ + 2e⁻ → Cu⁰.

In other chemical reactions, there is no change of oxidation number of elements.

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A chemical reaction has Hf,reactants = –1,023 kJ and Hf,products = –935.3 kJ. Which graph can be used to represent this reaction

natita [175]

Hey there!

The pathway will resemble a hill , The minimum amount of energy the reagents need to make the complex activated, is the activation energy , The difference in heights of the products and reactants will be equivalent to the difference in energies.:

ΔH = ( -1,023 kj ) - ( - 935,3 kj )

ΔH = -87.7 Kj

7 0

4 years ago

Read 2 more answers

If you lick boo boo and eat it, will you get sick?

maw [93]

Yes u probably would get sick.. I don't recommend trying :)

if u eat it- then ur technically eating yourself 0-0

6 0

3 years ago

There are 0.55 moles of carbon dioxide gas in a 15.0 L container. This container is at a temperature of 300 K. What is the press

sertanlavr [38]

Answer:

$\large \boxed{\text{D.) 91 kPa}}$

Explanation:

We can use the Ideal Gas Law — pV = nRT

Data:

V = 15.0 L

n = 0.55 mol

T = 300 K

Calculation:

$\begin{array}{rcl}pV & =& nRT\\p \times \text{15.0 L} & = & \text{0.55 mol} \times \text{8.31 kPa$\cdot$ L$\cdot$K$^{-1}$mol$^{-1}\times$ 300 K}\\15.0p & = & \text{1370 kPa}\\p & = & \textbf{91 kPa}\end{array}\\\text{The pressure in the container is $\large \boxed{\textbf{91 kPa}}$}$

6 0

3 years ago

Write the chemical equations involved in this experiment and how that the rate of disappearance of [S2O8^2-] is proportional to

Ne4ueva [31]

S₂O₈²⁻

(aq) + 2I⁻

(aq) → I₂(aq) + 2SO₄

²⁻(aq)

2S₂O₃²⁻

(aq) + I₂(aq) → S₄O₆²⁻

(aq) + 2I⁻

(aq)

<u>Explanation:</u>

S₂O₈²⁻

(aq) + 2I⁻

(aq) → I₂(aq) + 2SO₄

²⁻(aq)

To measure the rate of this reaction we must measure the rate of concentration change of one of the reactants or products. To do this, we will include (to the reacting S₂O₈

²⁻ and I⁻

i) a small amount of sodium thiosulfate, Na₂S₂O₃,

ii) some starch indicator.

The added Na₂S₂O₃ does not interfere with the rate of above reaction, but it does consume the I₂ as soon as it is formed.

2S₂O₃²⁻

(aq) + I₂(aq) → S₄O₆²⁻

(aq) + 2I⁻

(aq)

This reaction is much faster than the previous, so the conversion of I2 back to I⁻ is essentially instantaneous.

$rate = \frac{dI2}{dt} = \frac{1/2 [S2O3^2^-]}{t}$

5 0

3 years ago

A bond in which one atom contributes both bonding electrons to a covalentbond

yKpoI14uk [10]

<h3>Answer:</h3>

A coordinate bond

<h3>Explanation:</h3>

A chemical bond is a force of attraction between two or more atoms of elements.
Covalent bond is a type of chemical bond that occurs between non-metal atoms.
It occurs as a result of sharing of electrons between the non-metal atoms.
Atoms involved in covalent bond formation may contribute equally to the bond formation or the electrons shared may come form one of the atoms.
When the electrons shared in a covalent bond are derived from one atom, then the covalent bond is known as a coordinate bond.

4 0

3 years ago