The domain of the function is the set of all real numbers and the range of the function is the set of all values greater than -2
<h3>How to determine the domain and the range?</h3>
The function is given as:
f(x) = 2(x -4)^2 - 2
A quadratic function can take any real number as its input.
So, the domain of the function is the set of all real numbers
The vertex of the above function is:
Vertex = (4, -2)
And the leading coefficient is:
a = 2
The y value of the vertex is;
y = -2
Because the value of a is positive, then the vertex is a minimum.
This means that the range of the function is the set of all values greater than -2
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-x+y=2
y=2+x
5/3*x-2y=-2
5/3*x- 2 (2+x)= -2
5/3*x-4-2x=-2
5/3x -2x=4-2
x(5/3-2)=2
x(5/3-6/3)=6/3
x*(-1/3)=6/3
-x=6
x=-6
y=x+2
y=-6+2
y=-4
Step-by-step explanation:
Solution,
f(x) = -4x2 + 19
f(x)=-8+19
f(x)=27
As it is a constant function, therefore
f(-7)=27