0.1 M solution of a disaccharide solution will contain 2000 monosaccharide molecules.
<h3>What are monosaccharides?</h3>
Monosaccharides, also known as simple sugars are the simplest monomers of carbohydrates which may either be 3 carbon, 4 carbon, 5 carbon, 6 carbon or 7 carbo compounds.
There are two types of monosaccharides;
- aldoses sugars, e.g. glucose, and
- ketose sugars e.g. fructose.
When two monosaccharides are linked together by glycosidic bonds to form a single compound, the compound formed is called a disaccharide.
Considering the give question:
Suppose a 0.1M solution of a monosaccharide contains 1000 monosaccharide molecules. How many monosaccharide molecules would be in a 0.1 M solution of a disaccharide.
The number of monosaccharides molecules present in the 0.1 M solution of a disaccharide is determined as follows:
1 disaccharide molecule contains 2 monosaccharide molecules
0.1M solution of a monosaccharide contains 1000 monosaccharide molecules.
0.1 M solution of a disaccharide will contain 2 * 1000 monosaccharide molecules
0.1 M solution of a disaccharide will contain = 2000 monosaccharide molecules.
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Answer:
C. Disruptive Selection
Explanation:
Disruptive selection occurs when two extremes of continuous variation are favored more than intermediate traits.
The extremes of continuous variation exhibited in this species of snail is the color of their shell which allows them to blend with the background of their habitat.
The shady forest of the habitat makes the dark-shelled individuals to be better hidden from bird predators, while the light-shelled individuals are better hidden in well-lit brushy edge areas. This disruptive coloration exhibited by both individuals makes both individuals of this species of snail less vulnerable to predation.
Both individuals of this species both extremities would naturally survive in this habitat as snails with intermediate extremities would be highly preyed on since there is no area of intermediate brightness in the habitat to make them invisible to predators
A series of logical steps followed to solve problems.
Answer:
Hay infusion refers to an amalgamation that can be formed by taking samples from different sources like rivers, lakes, ponds, and others. It is one of the best procedures that can elevate the density of the bacteria cell at any specific time interval.
In the given case, even after boiling hay infusion for one hour, growth was observed in the flask after one day. It can be due to certain factors like the hay infusion may have been comprising some endospore, which is resistant to heat or may comprise some kinds of bacteria that can withstand high temperatures.
Because of which, even after heating the infusion for one hour, it did not get influenced by the heat and got the chance to grow when it got optimum temperature again at the time when the sample was left as such.
