Answer:
100.223°C is the boiling point of an aqueous solution.
Explanation:
Osmotic pressure of the solution = π = 10.50 atm
Temperature of the solution =T= 25 °C = 298 .15 K
Concentration of the solution = c
van'y Hoff factor = i = 1 (non electrolyte)


c = 0.429 mol/L = 0.429 mol/kg = m
(density of solution is the same as pure water)
m = molality of the solution
Elevation in boiling point = 


T = Boiling point of the pure solvent
= boiling point of the solution
= Molal elevation constant
We have :
(given)
m = 0.429 mol/kg
T = 100° C (water)




100.223°C is the boiling point of an aqueous solution.
<span>2Fe2O3(s) + 3C(s) →4 Fe(s) + 3CO2(g)
3 mol 3mol
4 mol x mol
x=4*3/3= 4.0 mol
</span>2Fe2O3(s) + 3C(s) →4 Fe(s) + 3CO2(g)<span>
2 mol 3 mol
14 mol x mol
x=14*3/2= 21.0 mol</span>
Given data:
Diameter of the gold wire (d) = 0.175 cm
Length of the gold wire (l) = 1.00 *
cm
Volume of the given gold wire = volume occupied by a cylindrical object\
= π *
*l
here r = radius of the cross section
where : r = d/2
Hence the volume V = π *
*l
= 
Density of gold = 19.3 g/cm3
Weight of the gold wire = Density * volume
=
*
= 
Answer: Time needed: 2.5 s
Distance covered: 31.3 m
Explanation:
I'll start with the distance covered while decelerating. Since you know that the initial speed of the car is 15.0 m/s, and that its final speed must by 10.0 m/s, you can use the known acceleration to determine the distance covered by
on one side of the equation and solve by plugging your values
To get the time needed to reach this speed, i.e. 10.0 m/s, you can use the following equation
Explanation: