Answer:
Electronegativity (χ) is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself. Atoms with higher electronegativity attracts more electrons towards it, electrons are closer to that atom.
Answer
For this we use ideal gas equation which is:
P1V1 = P2V2
P1 = 1.10 atm
V1 = 326 ml
P2 = 1.90
V2 = ?
By rearranging the ideal gas equation:
V2 = P1V1 ÷ P2
V2 = 1.10 × 326 ÷1.90
V2 = 358.6 ÷ 1.90
V2 = 188.7 ml
Answer:
The molar solubility of carbon dioxide gas is
.
Explanation:
Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.
To calculate the molar solubility, we use the equation given by Henry's law, which is:
![C_{CO_2}=K_H\times p_{liquid}](https://tex.z-dn.net/?f=C_%7BCO_2%7D%3DK_H%5Ctimes%20p_%7Bliquid%7D)
where,
= Henry's constant = ![3.50\times 10^{-2}mol/L.atm](https://tex.z-dn.net/?f=3.50%5Ctimes%2010%5E%7B-2%7Dmol%2FL.atm)
= partial pressure of carbonated drink
![p_{CO_2}=p\times \chi_{CO_2}](https://tex.z-dn.net/?f=p_%7BCO_2%7D%3Dp%5Ctimes%20%5Cchi_%7BCO_2%7D)
where = p = Total pressure = 0.400 atm
= mole fraction of ![CO_2=3.33\times 10^{-4}](https://tex.z-dn.net/?f=CO_2%3D3.33%5Ctimes%2010%5E%7B-4%7D)
![p_{CO_2}=0.400 atm\times 3.33\times 10^{-4} =0.0001332 atm](https://tex.z-dn.net/?f=p_%7BCO_2%7D%3D0.400%20atm%5Ctimes%203.33%5Ctimes%2010%5E%7B-4%7D%20%3D0.0001332%20atm)
Putting values in above equation, we get:
![C_{CO_2}=3.5\times 10^{-2}mol/L.atm\times 0.0001332 atm\\\\C_{CO_2}=4.662\times 10^{-6} M](https://tex.z-dn.net/?f=C_%7BCO_2%7D%3D3.5%5Ctimes%2010%5E%7B-2%7Dmol%2FL.atm%5Ctimes%200.0001332%20%20atm%5C%5C%5C%5CC_%7BCO_2%7D%3D4.662%5Ctimes%2010%5E%7B-6%7D%20M)
Hence, the molar solubility of carbon dioxide gas is
.
I think is is A. welding torches
Answer:NH4F ( ammonium fluoride)
Explanation:
NH4 is a cation with a positive 1 charge and F an anion having negative 1 oxidation number. Do the criss-cross rule for both cations and anions. So the charge of NH4 which is +1 will be the subscript of F and the charge of F which is -1 will be the subscript of NH4. Both have the same numerical value of 1 so we can cancel them out in the final equation of the chemical compound.