A car is traveling with an initial velocity of 15 m/s when the driver decides to go faster by accelerating at 5 m/s2 for 10 seco
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Answer:
Rate = 116m⁻¹s⁻¹[lactose][H]⁺
Explanation:
the formula for rate of reaction is given as
Rate = k[lactose]∧α[H]⁺∧β
we solve for the value of α and β
([lactose]₁/[lactose]₂)∧α
α =
when we divide this equation
α =
α = 1
we find β
R₁/R₂ = 0.01/0.02(0.001/0.001)∧β
0.00116/0.00232 = 0.5(1)∧β
β = 1
Rate = k[lactose]∧α[H]⁺∧β
we have to find the value for k
k = 0.00116/0.01(0.001)
k = 0.00116/0.00001
= 116m⁻¹s⁻¹
<u>Rate = 116m⁻¹s⁻¹[lactose][H]⁺</u>
Answer: The gravitational pull on Moon B is greater than on Moon A because Moon B is closer to the new planet than Moon A.
Explanation:
The gravitational force exerted by the two objects on each other is inversely proportional to the square of the distance between the objects.
F = gravitational force or pull
G = gravitational constant on that planet
M = mass of the object-1
m = mass of object-2(Mass of Moon-A or Moon-B)
r = distance between two objects
With decease in distance 'r' the force between the object increases or vice versa.So, from this we can say that the gravitational pull on Moon-B is more than the gravitational pull on Moon-A because the Moon B is closer than the Moon-A from the new planet.