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bija089 [108]
3 years ago
6

How much force is required to accelerate a 50 kg mass at 2 m/s2?

Physics
1 answer:
skelet666 [1.2K]3 years ago
5 0
Newton's 2nd law of motion: 

                    Force = (mass) x (acceleration)

                              = (50 kg) x (2 m/s²)

                              =    100 newtons .                                   
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A series circuit contains a 100.0-Ω resistor, a 0.450-H inductor, a 0.360-µF capacitor, and a time-varying source of emf providi
eduard

Answer:

A) The resonance angular frequency in an L-R-C circuit is

\omega_0 = \frac{1}{\sqrt{LC}} = \frac{1}{\sqrt{0.45\times0.36\times 10^{-6}}}\\\omega_0 = 2.48\times10^3 rad/s

B) The current can be found by calculating the impedance of the system.

Z = \sqrt{R^2 + (X_L - X_C)^2} = R

Since X_L = X_C at resonance.

So, I = V/Z = V/R = 30 / 100 = 0.3A

5 0
3 years ago
The motor in a refrigerator has a power output of 294 W. If the freezing compartment is at 271 K and the outside air is at 310 K
dusya [7]

Answer:

Maximum amount of heat = 10002151.38J

Explanation:

Workdone by motor in 86.1 minutes I given by:

W = power × time

W= 294 × 86.1×60

W= 1439424 Joules

W= 1.4 ×10^6Joules

The amount of heat extracted is given by:

/QL /= K/W/ = TL/W/ /(TH - TL)

Where TL= freezing compartment temperature

TH = Outside air temperature

/QL /= 271 × 1439424 / (310 - 271)

/QL/ = 390083904/39

/QL/ = 10002151.38 Joules

5 0
3 years ago
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Four different objects are placed on a number line at 0. The chart describes the motion of each object.
Ket [755]

Answer:

Z

Explanation:

8 0
3 years ago
The angular speed of the rotor in a centrifuge increases from 420 to 1420 rad/s in a time of 5.00 s. (a) Obtain the angle throug
9966 [12]

Answer:

a) θ = 2500 radians

b) α = 200 rad/s²

Explanation:

Using equations of motion,

θ = (w - w₀)t/2

θ = angle turned through = ?

w = final angular velocity = 1420 rad/s

w₀ = initial angular velocity = 420

t = time taken = 5s

θ = (1420 - 420) × 5/2 = 2500 rads

Again,

w = w₀ + αt

α = angular accelaration = ?

1420 = 420 + 5α

α = 1000/5 = 200 rad/s²

6 0
3 years ago
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When you push a child on a swing, your action is most effective when your pushes are timed to coincide with the natural frequenc
OleMash [197]

Answer:

T = 4.48 s

we can see that this time period is independent of the mass of the child so answer would be same if the child mass is different

Explanation:

Natural frequency of a simple pendulum of L length is given as

f = \frac{1}{2\pi}\sqrt{\frac{g}{L}}

so the time period of the oscillation is given as

T = 2\pi \sqrt{\frac{L}{g}}

so we will have

L = 5 m

T = 2\pi\sqrt{\frac{5}{9.81}}

T = 4.48 s

also from above formula we can see that this time period is independent of the mass of the child so answer would be same if the child mass is different

3 0
3 years ago
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