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3 years ago

How much force is required to accelerate a 50 kg mass at 2 m/s2?

Physics

1 answer:

skelet666 [1.2K]3 years ago

5 0

Newton's 2nd law of motion:

Force = (mass) x (acceleration)

= (50 kg) x (2 m/s²)

= 100 newtons .

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The _______ is a factor that's affected by changes in the independent variable. A. dependent variable B. hypothesis C. experimen

Irina18 [472]

A. dependent variable

As the the independent variable (i.e. number of cats being sold) increases, the dependent variable (i.e. money made) will also increase. You can have 1,000,000 cats for sale and make no money, but you cannot make money without having sold some cats first.
Hope my weird example helped!

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3 years ago

Read 2 more answers

Calculate the Force of Gravity acting on an object that has a mass of 1.3 kg. The object is on Earth so use 9.8m/s2 for the acce

sweet-ann [11.9K]

To calculate the gravitational force acting on an object given the mass and the acceleration due to gravity, use the following formula.

Fg = m • g
Fg = 1.3 kg • 9.8 m/s^2
Fg = 12.74 N or about 12.7 N.

The solution is C. 12.7 N.

7 0

3 years ago

Sandy is whirling a ball attached to a string in a horizontal circle over his head. If Sandy doubles the speed of the ball, what

jeka57 [31]

The tension in the string B) It quadruples.

Explanation:

The ball is in uniform circular motion in a horizontal circle, so the tension in the string is providing the centripetal force that keeps the ball in circular motion. So we can write:

$T= m\frac{v^2}{r}$

where:

T is the tension in the string

m is the mass of the ball

v is the speed of the ball

r is the radius of the circle (the lenght of the string)

In this problem, we are told that the speed of the ball is doubled, so

v' = 2v

Substituting into the previous equation, we find the new tension in the string:

$T' = m \frac{(2v)^2}{r}=4(m\frac{v^2}{r})=4T$

Therefore, the tension in the string will quadruple.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

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3 years ago

The shadow cast by a simple stick or obelisk allowed ancient people to______________.

Sphinxa [80]

Answer:

B. tell the time of day

Explanation:

Solar watch. It was one of the few ways to measure time in antiquity, but it has not ceased to be a useful and also curious instrument. Nowadays, it not only allows us to know the time and day of the year, but it is also used to know some characteristics of the Sun, even with the absence of solar radiation, and provides its aesthetic value. With a suitable design, the solar clock allows to know, for example, the sunrise and sunset times for any day of the year; the duration of day and night; at what time, according to the date, direct solar radiation affects each wall according to its North, South, East or West orientation; and the position of the Sun at any time and day of the year, either by day or by night. It also allows orientation, since the solar clock indicates the position of the Polar Star.

The solar clock can have different shapes, commonly on vertical, horizontal or inclined flat surfaces. A solar clock can be made on curved and irregular surfaces, and even inside a closed restaurant or lounge. In the latter case it would not be the shadow that would give the time, but a solar ray that is allowed to enter the room

6 0

4 years ago

All other things being equal, current will be larger in a wire that has a larger value of All other things being equal, current

morpeh [17]

Answer:

a) conductivity

Explanation:

Assuming the wire obeys Ohm's Law, for a given voltage, in order to have a larger current, the resistance must be lower.
The resistance of a resistive element is given by the following equation:

$R = \rho * \frac{L}{A}$

If geometric parameters keep the same, the only choice to lower the resistance value is diminishing the resistivity ρ.
The resistivity, indeed, is defined as the inverse of the conductivity, σ.
So, if resistivity decreases, conductivity increases.
So, in order to have a larger current, all other things being equal, the wire must have a larger value of conductivity.
The option a) is the right one.

7 0

3 years ago