Eaither D or A bit I am leaning more towards D
Answer:
The force required to begin to lift the pole from the end 'A' is 240 N
Explanation:
The given parameters for the pole AB are;
The length of the pole, l = 10.0 m
The weight of the pole, W = 600 N ↓
The distance of the center of gravity of the pole from the side 'A' = 4.0 m
Let '
' represent the force required to begin to lift the pole from the end 'A' and let a force applied in the upwards direction be positive
For equilibrium, the sum of moment about the point 'B' = 0, therefore, taking moment about 'B', we have
× 10.0 m - W × 4.0 m = 0
∴
× 10.0 m = W × 4.0 m = 600 N × 4.0 m
× 10.0 m = 600 N × 4.0 m
∴
= 600 N × 4.0 m/(10.0 m) = 240 N
The force required to begin to lift the pole from the end 'A',
= 240 N.
The average velocity is -4.17 m/s
Explanation:
The average velocity of a body is given by:

where
d is the displacement of the body
t is the time elapsed
For the student in this problem, we have:
Initial position: 
Final position: 
So the displacement is

The time elapsed is
t = 60 s
Therefore, the average velocity is

Where the negative sign means the student is moving towards the origin.
Learn more about average speed and velocity:
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Answer:
44.492 kg
Explanation:
Convert pounds to kilograms.
1 lb = 0.454 kg
98 lb * 0.454 kg =44.492 kg