Answer:
a) IUPAC Names:
1) (<em>trans</em>)-but-2-ene
2) (<em>cis</em>)-but-2-ene
3) but-1-ene
b) Balance Equation:
C₄H₁₀O + H₃PO₄ → C₄H₈ + H₂O + H₃PO₄
As H₃PO₄ is catalyst and remains unchanged so we can also write as,
C₄H₁₀O → C₄H₈ + H₂O
c) Rule:
When more than one alkene products are possible then the one thermodynamically stable is favored. Thermodynamically more substituted alkenes are stable. Furthermore, trans alkenes are more stable than cis alkenes. Hence, in our case the major product is trans alkene followed by cis. The minor alkene is the 1-butene as it is less substituted.
d) C is not Geometrical Isomer:
For any alkene to demonstrate geometrical isomerism it is important that there must be two different geminal substituents attached to both carbon atoms. In 1-butene one carbon has same geminal substituents (i.e H atoms). Hence, it can not give geometrical isomers.
I believe that is a plant called Wisteria.
The frequency and energy of most energetic of these photons is
Hz and 
J respectively.
The high energy photons will have least wavelength. Taking the given less wavelength for calculation of frequency and energy of photons.
λ = 2200 Å
Also, we know, 1 Å = 
m
So, λ = 
λ = 
<em> </em>m
Now, calculating frequency using the formula -
c = fλ, where c is speed of light, f is frequency and λ is wavelength.
We know, c = 
m/s
f = c/λ
f = 
frequency = Hz
Now, calculating Energy through the formula -
E = hf, where E is energy, h is planck's constant and f is frequency
Value of planck's constant = 
Js
E = *
Energy = J
Thus, frequency and energy of photons is Hz and J respectively.
Learn more about energy of photon -
brainly.com/question/15946945
#SPJ4
1 calcium chloride is equal to <span> 0.00901030779211 mole.
if we just multiply that by 37.793 we get </span><span>0.34052656238 moles of calcium chloride.</span>
First reaction is a Condensation Reaction. As a amall molecule (water) is evolved with the production of ether this is called as condensation of alcohols.
Second reaction is Addition Reaction also known as electrophilic addition reaction. Here HBr is added across double bond to yield alkyl halide.
Third reaction is Elimination Reaction. In this reaction tertiary alcohol is treated with base. A unsaturated compound is formed in this reaction.
Last reaction is Substitution Reaction (Aromatic Electrophilic substitution reaction. In this case a electrophile on benzene (Proton) is substituted with another electrophile (Bromine)
