Question

Write the formulas for the following ionic compounds: (a) sodium oxide, (b) iron sulfide (containing the Fe2+ ion),(c) cobalt sulfate (containing the CO3+ and (SO4)^-2 ions), (d) barium fluoride.

Answer 1

Answer:

Explanation:

a) Na₂O

b) FeS

c)Co₂(SO₄)₃

d) BaF₂

Answer 2

Answer : The correct formula of the given compound will be:

(a) $Na_2O$

(b) $FeS$

(c) $Co_2(SO_4)_3$

(d) $BaF_2$

Explanation :

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

The nomenclature of ionic compounds is given by:

1. Positive ion is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.

(a) sodium oxide

Sodium oxide is an ionic compound because sodium element is a metal and oxygen element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on sodium is (+1) and the the charge on oxygen is (-2). Thus, the formula of the compound sodium oxide will be $Na_2O$

(b) iron sulfide

Iron sulfide is an ionic compound because iron element is a metal and sulfur element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on iron is (+2) and the the charge on sulfur is (-2). Thus, the formula of the compound iron sulfide will be $FeS$

(c) cobalt sulfate

Cobalt sulfate is an ionic compound because cobalt element is a metal and sulfur element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on cobalt is (+3) and the the charge on sulfate is (-2). Thus, the formula of the compound cobalt sulfate will be $Co_2(SO_4)_3$

(d) barium fluoride

Barium fluoride is an ionic compound because barium element is a metal and fluorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The charge on barium is (+2) and the the charge on fluorine is (-1). Thus, the formula of the compound barium fluoride will be $BaF_2$