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Nat2105 [25]
3 years ago
13

You have some cash. You can either invest in a short-term bond that pays 4% or payoff some credit card debt at 9%. Which should

you do?
Mathematics
1 answer:
galben [10]3 years ago
6 0
Pay the credit card debt off.
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What are the solutions to the equation x - 7/x = 6
bearhunter [10]

The answer is C that is X=7 and X=-1

multiple x through the given equation to get rid of a fraction. It will be

{x}^{2}  - 7 = 6x

After that bring 6X to the LHS of the equation

so that it will look like the general equation that is

{x}^{2}  - 6x - 7 = 0

Use the quadratic formula (or any other approach to find the values of x

You will arrive at

x = 7. - 1

3 0
3 years ago
Katherine and Shally had $288 altogether. Katherine gave 1/3 of her share to Shally and their father gave $68 to Shally. They no
erastova [34]
1/3 of $288 is $96 So, therefore Shally had $96 at first.
But They both didn't have the same amount of money after too because:
1/3 of $288 is $96 
$96 + $68 = $164     So Shally has $164

Now, $288 - $96 = $192.    So Katherine has $192

So therefore they did not have the same amount of money but 1/3 of $288 is $96
 

4 0
3 years ago
How are the shapes alike
Andrews [41]

Answer:

Each circle (A, B, and C) contain shapes that all share at least one characteristic. Some shapes are contained in more than one circle because they share more than one characteristic. For example, shape 3 fits the rule for circles A and B, but not circle C. It lies within circles A and B, but not circle C.

Step-by-step explanation:

3 0
3 years ago
Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


5 0
3 years ago
The steam and the leaf plot list the ages of customers in a book store
WINSTONCH [101]

Answer:

Step-by-step explanation:

4 0
3 years ago
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