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AleksandrR [38]
3 years ago
6

Using the periodic table, complete the table to describe each atom. Type in your answers.

Chemistry
1 answer:
sladkih [1.3K]3 years ago
5 0
Where's the image?


please enter a image below so I can help.
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Tudy the image above. Which statement below best explains the steps of tornado formation?
Reil [10]

C) Step 1: a horizontal spinning effect is formed from wind shear

Step 2: warm rising air shifts the horizontal rotation to a vertical rotation

Step 3: the vertical rotation expands and extends

7 0
3 years ago
Nh3 is a weak base (kb = 1.8 × 10–5 m) and so the salt nh4cl acts as a weak acid. what is the ph of a solution that is 0.013 m i
ankoles [38]
First, we need to get the value of Ka:

when Ka = Kw / Kb 

we have Kb = 1.8 x 10^-5 

and Kw = 3.99 x 10^-16  so, by substitution:

Ka = (3.99 x 10^-16) /  (1.8 x 10^-5) = 2.2 x 10^-11

by using the ICE table :

                 NH4+  + H2O →NH3 +  H+
intial          0.013                       0         0 

change       -X                          +X      +X

Equ        (0.013-X)                      X         X

when Ka = [NH3][H+] / [NH4+] 

by substitution:

2.2 x 10^-11 = X^2 / (0.013 - X)  by solving this equation for X

∴X = 5.35 x 10^-7

∴[H+] = X = 5.35 x 10^-7

∴PH = - ㏒[H+]
 
        = -㏒(5.35 x 10^-7)
        = 6.27
6 0
3 years ago
H₂ (2)<br> → H.<br> H₂(8)<br> +<br> 2(g)<br> wer
Gre4nikov [31]

The given question is incomplete. The complete question is:

In the chemical reaction: , with 8 grams of and 16 grams of and the reaction goes to completion, what is the excess reactant and how much of that would remain?

A) 6 grams of  

B) 7 grams of  

C) 8 grams of

D) 12 grams of

E) 14 grams of

Answer: A) 6 grams of H_2

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} H_2=\frac{8g}{2g/mol}=4moles

\text{Moles of} O_2=\frac{16g}{32g/mol}=0.5moles

2H_2(g)+O_2(g)\rightarrow 2H_2O(g)  

According to stoichiometry :

1 moles of O_2 require 2 moles of H_2

Thus 0.5 moles of O_2 will require=\frac{2}{1}\times 0.5=1.0moles  of H_2

Thus O_2 is the limiting reagent as it limits the formation of product and H_2 is the excess reagent.

(4.0-1.0) = 3.0 moles of  are left unreacted

Mass of remained=

Thus 6.0 g of H_2 will remain.

4 0
2 years ago
What is the difference between covalent bonds and ionic bonds masteringbiology?
harina [27]
Ionic bonds involve the transfer of electrons from metal to non metal
covalent bonds involve sharing of electrons between two non metal
7 0
3 years ago
This wood screw is a simple machine. It is
Ilia_Sergeevich [38]
I think the answer is D

8 0
3 years ago
Read 2 more answers
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