Answer:
15.0 mL
Explanation:
Please see the step-by-step solution in the picture attached below.
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Answer:
37.3
263.5
Explanation:
The scale measures hundreds of units, tens of units, units, and parts of units (1 decimal place.
Scale 1
Hundreds 0 * 100 = 0
Tens: 3 * 10 = 30
Units: 7 * 1 = 7
1/10 unit = 3* 0.1 = 0.3
Total 30 + 7 + 0.3 = 37.3
Scale 2
Hundreds 2 * 100 = 200
Tens: 6 * 10 = 60
Units: 3 * 1 = 3
1/10 unit = 5* 0.1 = 0.5
Total = 200 + 60 + 3 + 0.5 = 263.5
Answer:
We need 8.11 grams of glucose for this solution
Explanation:
Step 1: Data given
Molarity of the glucose solution = 0.300 M
Total volume = 0.150 L
The molecular weight of glucose = 180.16 g/mol
Step 2: Calculate moles of glucose in the solution
Moles glucose = molarity solution * volume
Moles glucose = 0.300 M * 0.150 L
Moles glucose = 0.045 moles glucose
Step 3: Calculate mass of glucose
MAss glucose = moles glucose* molecular weight of glucose
MAss glucose = 0.045 moles * 180.16 g/mol
MAss glucose = 8.11 grams
We need 8.11 grams of glucose for this solution
His measurements are precise since his pH values are close to each other in a way that it was repeated in all measurements. On the contrary to accuracy, it is the closeness to the actual pH value he should have achieved. Therefore, Jose's results are precise but not accurate since his value is not close to the actual value of pH 4.
