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Levart [38]
2 years ago
6

How many moles of xenon gas are necessary to exert a 0.64atm pressure in an 8.5L container at 300.0K?

Chemistry
2 answers:
navik [9.2K]2 years ago
5 0

0.026 moles is the right answer.

Sindrei [870]2 years ago
3 0

Answer:

0.026 moles

Explanation:

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Which represents the self ionization of water at 25 degrees
gayaneshka [121]
This question comes with four answer choices:

<span>A. H2O + H2O ⇄ 2H2 + O2

B. H2O + H2O⇄  H2O2 + H2

C. H2O + H2O ⇄ 4H+ + 2O2-

D. H2O + H2O ⇄  H3O+ + OH-

Answer: option </span><span>D. H2O + H2O ⇄  H3O+ + OH-

(the +sign next to H3O is a superscript, as well as the - sing next to OH)

Explanation:

The self-ionization of water, or autodissociation, produces the two ions H3O(+) and OH(-). The presence of ions is what explain the electrical conductivity of pure water.

</span><span>In this, one molecule of H2O loses a proton (H+) (deprotonates) to become a hydroxide ion, OH−. Then, he <span>hydrogen ion, H+</span>, immediately protonates another water molecule to form hydronium, H3O+.
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3 years ago
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Zanzabum
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Making solutions is an extremely important component to real-life chemistry. If you make 3.00 L of a solution using 90.0 g of so
kumpel [21]

Answer:

Final concentration of NaOH = 0.75 M

Explanation:

For NaOH :-

Given mass = 90.0 g

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{90.0\ g}{39.997\ g/mol}

Moles\ of\ NaOH= 2.2502\ mol

Molarity is defined as the number of moles present in one liter of the solution. It is basically the ratio of the moles of the solute to the liters of the solution.

The expression for the molarity, according to its definition is shown below as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Where, Volume must be in Liter.

It is denoted by M.

Given, Volume = 3.00 L

So,

Molarity=\frac{2.2502\ mol}{3.00\ L}=0.75\ M

<u>Final concentration of NaOH = 0.75 M</u>

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3 years ago
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In pure water, all of the molecules in the liquid are water molecules so the mole fraction is 1 (100 % H2O, 55 mol/L). In sea water, the concentration of water molecules in the solution is less than that of pure water so the vapor pressure of sea water is also lower.
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