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DerKrebs [107]
3 years ago
9

A double-slit diffraction pattern is formed on a distant screen. If the separation between the slits decreases, then

Physics
2 answers:
Kaylis [27]3 years ago
6 0

Answer:

  • this shows that on decreasing the distance between the slits:
  • the distance from the central fringe will increase.
  • order of fringes will decrease.

Explanation:

We have the mathematical expression for the Young's double slit experiment as:

\lambda=\frac{x.d}{n.l} .....................(1)

where:

\lambda = wavelength of the monochromatic light used.

x = distance from the central fringe

n = order of fringes

d = distance between the slits.

l = distance between the slit and the screen.

Equation (1) can be re-written as:

d=\frac{\lambda.n.l}{x}

  • this shows that on decreasing the distance between the slits:
  • the distance from the central fringe will increase.
  • order of fringes will decrease.

While the frequency of light will be constant & distance between the slit and the screen is also kept constant.

Scorpion4ik [409]3 years ago
5 0

Answer:

y = \frac{ \lambda D}{d}

From the expression given above we can notice that if separation between the given slits decreased then distance between fringes increase. since the distance between any two fringes is inversely proportional to separation between any given plates. Therefore, distance between the fringes increased

Explanation:

The distance between interference fringe for small angle is

y = \frac{ \lambda D}{d}

here,

\lambda denote wavelength of light

D is the distance between slits and the screen

d is separation of silts

From the expression given above we can notice that if separation between the given slits decreased then distance between fringes increase. since the distance between any two fringes is inversely proportional to separation between any given plates. Therefore, distance between the fringes increased

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Two soccer players, Mia and Alice, are running as Alice passes the ball to Mia. Mia is running due north with a speed of 5.30 m/
Tju [1.3M]

Answer:

a) v_{p}  = 2.83 m / s ,  b)  50.5º north east

Explanation:

This is a vector problem.

         v_{bg} = v_{bm} + v_{mg}

The speed of the ball with respect to the ground is the speed of the ball with respect to Mia plus the speed of Mia with respect to the ground

To make the sum we decompose the speed of the ball in its components

The angle of 30 east of the south, measured from the positive side of the x axis is

             θ = 30 + 270 = 300

            v_{bx} = v_{b} cos 300

             v_{by} = v_{b} sin. 300

             v_{bx} = 3.60 cos 300 = 1.8 m / s

             v_{by} = 3.60 sin 300 = -3,118 m / s

Let's add speeds on each axis

X axis

            vₓ = v_{bx}

             vₓ = 1.8 m / s

Y Axis  

             v_{y} = v1 - vpy

             v_{y} = 5.30 - 3.118

             v_{y} = 2.182 m / s

The magnitude of the velocity can be found using the Pythagorean theorem

              v_{p} = √ (vₓ² + v_{y}²)

               v_{p} = √ (1.8² + 2.182²)

               v_{p} = 2,829 m / s

               v_{p}  = 2.83 m / s

b) for direction use trigonometry

              tan θ = v_{y} / vₓ

              θ = tan ⁺¹ v_{y} / vₓ

              θ = tan⁻¹ 2.182 / 1.8

         Tea = 50.48º

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Based on scientific data, the stone is accelerated at approximately 10 m/s^2.

<u>Given the following data:</u>

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<h3>What is gravity?</h3>

Gravity can be defined as a force of attraction that controls the movement of the planets such as Earth around the Sun.

This ultimately implies that, gravity is a universal force of attraction that acts between all objects or matter that are having both mass and energy, and can occupy space.

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Furthermore, the gravity near the Earth's surface generally makes it possible for all physical objects such as stones to possess weight and experience a free fall.

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