Vertical Asymptotes:
X= -1, 1
Oh my gosh we have the same question I been looking for
1) 3x+y+z=4
2) 2x+2y+3z=3
3) x+3y+2z = 5
1)*2 6x + 2y + 2z = 8
2) 2x + 2y +3z = 3
- __________________
4x - z = 5
2)*3 6x + 6y + 9z = 9
3)*2 2x + 6y + 4z = 10
- __________________
<span>4x+5z =-1
</span>
4x+5z = -1
4x - z =5
- ________
6z = -6
<u>z = -1
</u><u /><u>
</u>If z=-1,
4x -(-1) =5
4x = 5-1
x = 4/4
<u>x=1</u>
3x+y+z=4
3(1)+y+(-1)=4
3+y-1=4
<u>y=2
So z=-1, x=1, y=2</u>

=

Multiply both sides by 12, so that we get rid of the fraction in x.
12 · (x+3)/12 = 2/7 · 12
Simplify.
x + 3 = 24/7
Then, subtract 3 from both sides, so that "x" gets isolated.
x = 24/7 - 3
Turn "3" into an improper fraction so that we could find the value of x easier.
3 = 21/3
So :
x = 24/7 - 21/7
Simplify.
x = 3/7
~Hope this helps!~
Simply cross multiply and simplify to get a = 11
Hope this helped!! xx