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Leviafan [203]
3 years ago
14

If an object doubles in mass, what happens to its momentum? Explain why.

Physics
1 answer:
Umnica [9.8K]3 years ago
4 0
Its momentum doubles as well. Considering momentum equals M•V. Regardless of velocity (except if it’s not moving, in that case it doesn’t have any momentum) it will be double.
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After creating a question and forming a hypothesis, what is the next step in the scientific method
Keith_Richards [23]
The next step is to create research
3 0
3 years ago
If you increase the frequency of a sound wave four times, what will happen to its speed?
ozzi

The speed will increase four (4) times when the frequency of sound wave is increased four (4) times.

<h3>How to calculate the frequency of a wave.</h3>

Mathematically, the frequency of a sound wave is given by this formula:

F = \frac{V}{\lambda}

<u>Where:</u>

  • F is the frequency of a sound wave.
  • V is the velocity of a sound wave.
  • \lambda is the wavelength of a sound wave.

<u>Note:</u> The frequency of the sound wave is increased four (4) times.

  • F = 4F

Substituting the given parameters into the formula, we have;

4F = \frac{V}{\lambda}\\\\V=4F\lambda

Therefore, the speed will increase four (4) times when the frequency of sound wave is increased four (4) times.

Read more on sound wave here: brainly.com/question/19250621

4 0
3 years ago
A catcher catches a 150g baseball traveling horizontally at 25 m/s. If the ball takes 20.ms to stop once it is in contact with t
rosijanka [135]

Answer:

The magnitude of the force exerted by the ball on the catcher is 1.9 × 10²  N

Explanation:

Hi there!

Let´s find the acceleration of the ball that makes it stop when caught by the catcher. The acceleration can be calculated from the equation of velocity considering that it is constant:

v = v0 + a · t

We know that initially the ball was traveling at 25 m/s, so, if we consider the position of the catcher as the origin of the frame of reference, then, v0 = -25 m/s. We also know that it takes the ball 20 ms (0.02 s) to stop (i.e. to reach a velocity of 0). Then using the equation of velocity:

v = v0 + a · t

0 m/s = -25 m/s + a · 0.020 s

25 m/s/ 0.020 s = a

Now, using the second law of Newton, we can calculate the force exerted by the catcher on the ball:

F = m · a

Where:

F = force.

m = mass of the ball.

a = acceleration.

F = 0.150 kg · (25 m/s/ 0.020 s) = 1.9 × 10²  N

According to Newton´s third law, the force exerted by the ball on the catcher will be of equal magnitude but opposite direction. Then, the force exerted by the ball on the catcher will have a magnitude of 1.9 × 10²  N.

3 0
4 years ago
Please guys i need help in this
JulijaS [17]

Answer:

10 seconds

Explanation:

We have the equation V = at  (speed = acceleration x time)

We want to find the time, so can rearrange to T = V/a (time = speed / acceleration).

From the question, we know V is 5 and a is 0.5.

Now we can substitute that into our equation: 5/0.5 = 10.

So the time is 10 seconds.

Hope this helps! Let me know if you have any questions :)

8 0
3 years ago
A falling object with a mass of 2.55 kg encounters 4.0 N of air resistance. What is the acceleration of the object? (Choose up t
mel-nik [20]

The acceleration of the falling object with a mass of 2.55 kg that encounters 4.0 N of air resistance is 1.57m/s².

<h3>How to calculate acceleration?</h3>

Acceleration is change of velocity with respect to time (can include deceleration or changing direction).

The acceleration of a body can be calculated by using the following expression;

a = F/m

Where;

  • a = acceleration (m/s²)
  • F = force (N)
  • m = mass (kg)

According to this question, a mass of 2.55 kg encounters 4.0 N of air resistance. The acceleration of the object can be calculated as follows:

a = 4N ÷ 2.55kg

a = 1.57m/s²

Therefore, 1.57m/s² is the acceleration of the object.

Learn more about acceleration at: brainly.com/question/28767690

#SPJ1

4 0
1 year ago
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