Explanation:
It is given that,
Length of wire, l = 0.53 m
Current, I = 0.2 A
(1.) Approximate formula:
We need to find the magnitude of the magnetic field made by the current at a location 2.0 cm from the wire, r = 2 cm = 0.02 m
The formula for magnetic field at some distance from the wire is given by :
B = 0.000002 T
(2) Exact formula:
B = 0.00000199 T
or
B = 0.000002 T
Hence, this is the required solution.
Answer:
a = (V2 - V1) / t = (0 - 14.6) / 3 = -4.87 m/s^2
It might be useful to convert 14.6 m/s to mph
14.6 m/s * 39.37 in/m = 575 in /s
575 in/s / 12 in/ft = 47.9 ft/sec
47.9 ft/s / 88 ft/sec * 60 mph = 32.6 mph
Answer:
1.74 m/s
Explanation:
From the question, we are given that the mass of the an object, m1= 2.7 kilogram(kg) and the mass of the can,m(can) is 0.72 Kilogram (kg). The velocity of the mass of an object(m1) , V1 is 1.1 metre per seconds(m/s) and the velocity of the mass of can[m(can)], V(can) is unknown- this is what we are to find.
Therefore, using the formula below, we can calculate the speed of the can, V(can);
===> Mass of object,m1 × velocity of object, V1 = mass of the can[m(can)] × velocity is of the can[V(can)].----------------------------------------------------(1).
Since the question says the collision was elastic, we use the formula below
Slotting in the given values into the equation (1) above, we have;
1/2×M1×V^2(initial velocity of the first object) + 1/2 ×M(can)×V^2(final velocy of the first object)= 1/2 × M1 × V^2 m( initial velocity of the first object).
Therefore, final velocity of the can= 2M1V1/M1+M2.
==> 2×2.7×1.1/ 2.7 + 0.72.
The velocity of the can after collision = 1.74 m/s
Answer:
Explanation:
= Actual wavelength = 
= Relative permittivity = 1.44
The observed wavelength in the glass is given by
The wavelength lies in the range of green light.
Hence, the observed color of light is
