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tia_tia [17]
3 years ago
11

Answer this question, please. ______ interference occurs when two waves are in phase.

Physics
1 answer:
evablogger [386]3 years ago
3 0

Answer:

constructive interference

Explanation:

waves come together so that they are in phase with each other

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An electrician must decide between 3 heaters. The wire that she is using is rated 15A maximum, anything beyond that is a fire ha
lutik1710 [3]
Use the formula: P=IV, where P is power (watts), I is current (amperes) and V is potential difference (volts).

For the first heater:
900W = I_{1}*120V
I_{1} = 7.5A


For the second heater:
1800W = I_{2}*120V
I_{2} = 15A


For the third heater:
3000W = I_{3}*240V
I_{3} = 12.5A
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Help me pretty please
aleksklad [387]

Answer:a

Explanation:

4 0
3 years ago
I need help on this one please
klio [65]

Lithium shares more properties with Sodium, because they have the same number of valence electrons (one). Choice 1 is correct. Hope this helps!

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3 years ago
Match each type of wave to the way it moves.
OverLord2011 [107]

Answer:

Transverse wave- Back and forth at right angles to the direction of the wave arrow.

longitudinal wave- bask and forth in the direction of the motion of the motion of the wave.

electromagnetic wave- two alternating waves moving at right angles to each other.

Explanation:

In a longitudinal wave, the particles vibrate at right angles in reference to the wave motion.

In a transverse wave, the particles vibrate parallel to the wave motion

Electromagnetic waves occur as a result of the interaction between two  waves and are normally transverse in nature.  

8 0
4 years ago
. Two identical blocks, each of mass M, are connected by a massless string over a pulley of radius R and moment of inertia I. Th
Dima020 [189]

The angular acceleration of a pulley is described under the equation,

\theta = (0.5) \alpha t^2

So things clearing,

\alpha = \frac{ 2\theta}{t^2}

b) For point B it is necessary to make a sum of Forces,

\sum F=0

In this way,

Mg - T_1 = Ma

T_1 = Mg - Ma (1)

For block 2, we have the following relationship,

T_2 = Ma (2)

So,

T_1 - T_2 = I \frac{a}{R} (3)

Substituting (1) and (2) in (3)

Mg - Ma - Ma = I \frac{a}{R}

So,

a = \frac{2\theta R}{t^2}

<em>**Note that</em> \alpha R = a

c) For this point we need to use (1)

T1 = Mg - Ma = Mg - \frac{M^2\theta R}{t^2}

using (2)

RT_2=RT_1-I\alpha

T_2= \frac{RM(g-\frac{2\theta R}{t^2})-I\frac{2\theta}{t^2}}{R}

T_2=\frac{RMgt^2-2R^2M\theta-2t\theta}{Rt^2}

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3 years ago
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