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m_a_m_a [10]
3 years ago
6

A 1.0 kg mass at the end of a spring has an amplitude of 0.10 m and vibrates 2.0 times per second. What is its velocity when it

is 0.10 m from equilibrium.
Physics
1 answer:
PIT_PIT [208]3 years ago
5 0

Answer:

v=0m/s

Explanation:

From the question we are told that

Mass of objectM=10kg

AmplitudeA=0.10m

SHM w=2.0 times per second.

Distance from equilibrium 0.10m

Generally the equation for SHM displacement from equilibrium position is mathematically given by

v=Aw\sqrt{1-\frac{x^2}{A^2}}

For x=0.10

Therefore

v=Aw\sqrt{1-\frac{0.10^2}{A^2}}

v=0.10*2\sqrt{1-\frac{0.10^2}{0.10^2}}

v=0.10*2\sqrt{1-1}

v=0m/s

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