Answer:
m₁ / m₂ = 1.3
Explanation:
We can work this problem with the moment, the system is formed by the two particles
The moment is conserved, to simulate the system the particles initially move with a moment and suppose a shock where the particular that, without speed, this determines that if you center, you should be stationary, which creates a moment equal to zero
p₀o = m₁ v₁ + m₂ v₂
pf = 0
m₁ v₁ + m₂ v₂ = 0
m₁ / m₂ = -v₂ / v₁
m₁ / m₂= - (-6.2) / 4.7
m₁ / m₂ = 1.3
Another way to solve this exercise is to use the mass center relationship
Xcm = 1/M (m₁ x₁ + m₂ x₂)
We derive from time
Vcm = 1/M (m₁ v₁ + m₂v₂)
As they say the velocity of the center of zero masses
0 = 1/M (m₁ v₁ + m₂v₂)
m₁ v₁ + m₂v₂ = 0
m₁ / m₂ = -v₂ / v₁
m₁ / m₂ = 1.3
Answer:
The average speed would be 279.167 meters per second.
Explanation:
Speed is the magnitude that expresses the variation in position of an object and as a function of time. In other words, speed is defined as the relationship established between the distance traveled and the time elapsed in the movement of a mobile.
Speed can be calculated using the following expression:

In this case:
- distance= 7,035 km
- time= 7 hours
Since the required unit of speed is meter per second, then you convert from km to meters for the case of distance, and from hours to seconds for the case of time. So:
- distance= 7,035 km= 7,035,000 m (being 1 km= 1,000 m)
- time= 7 hours= 420 minutes= 25,200 seconds (being 1 hour=60 minutes and 1 minute=60 seconds)
Replacing in the definition of speed:

Solving:

Then, <u><em>the average speed would be 279.167 meters per second.</em></u>
Answer:
In collision between equal-mass objects, each object experiences the same acceleration, because of equal force exerted on both objects.
Explanation:
In a collision two objects, there is a force exerted on both objects that causes an acceleration of both objects. These forces that act on both objects are equal in magnitude and opposite in direction.
Thus, in collision between equal-mass objects, each object experiences the same acceleration, because of equal force exerted on both objects.
Answer:x=79,202.77 ft
Explanation:
Given
plane is at a height of 32000 ft
angle of depression is 
let x the distance between the point directly below the plane and airport be x
from diagram


x=79,202.77 ft
distance between plane and airport


h=85,422.94 ft
Answer with Explanation:
Mass of block=1.1 kg
Th force applied on block is given by
F(x)=
Initial position of the block=x=0
Initial velocity of block=
a.We have to find the kinetic energy of the block when it passes through x=2.0 m.
Initial kinetic energy=
Work energy theorem:

Where
Final kinetic energy
=Initial kinetic energy

Substitute the values then we get

Because work done=

![K_f=[2.4x-\frac{x^3}{3}]^{2}_{0}](https://tex.z-dn.net/?f=K_f%3D%5B2.4x-%5Cfrac%7Bx%5E3%7D%7B3%7D%5D%5E%7B2%7D_%7B0%7D)

Hence, the kinetic energy of the block as it passes thorough x=2 m=2.13 J
b.Kinetic energy =
When the kinetic energy is maximum then 





Substitute x=

Substitute x=

Hence, the kinetic energy is maximum at x=
Again by work energy theorem , the maximum kinetic energy of the block between x=0 and x=2.0 m is given by

![k_f=[2.4x-\frac{x^3}{3}]^{\sqrt{2.4}}_{0}](https://tex.z-dn.net/?f=k_f%3D%5B2.4x-%5Cfrac%7Bx%5E3%7D%7B3%7D%5D%5E%7B%5Csqrt%7B2.4%7D%7D_%7B0%7D)

Hence, the maximum energy of the block between x=0 and x=2 m=2.48 J