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jonny [76]
3 years ago
14

Which statements about cirrus clouds are true? Choose all answers that are correct. A. Cirrus clouds form high in the sky. B. Ci

rrus clouds usually mean fair weather. C. Cirrus clouds near the ground are called fog. D. Cirrus clouds are ice crystals that look like wispy streamers. please dont report
Physics
2 answers:
devlian [24]3 years ago
6 0
If i am correct the answer should be C
Vesna [10]3 years ago
5 0
A is the answr hope i helped
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Help with 7,8,9 please!!
Marysya12 [62]

# 7 the answer is 4) because you need opposites in order to attract

# 8 I'm going to guess it is 4) because electricity is needed in order a light bolt to work.(don't take my word for this one I'm not sure but, the other answer are correct)

# 9  the answer is 4) because the comb dose collect negative charges from the hair in order to make the hair have positive charge.


Hope this helped : )

4 0
2 years ago
What is the frequency of sound waves whose wavelength is 0.25 m on a day when the air temperature is 25 degree Celsius? Group of
Dvinal [7]

Answer:1384 Hz

Explanation:

Given

wavelength(\lambda )=0.25 m

Temperature T=25^{\circ}

at T=25^{\circ} velocity of sound is 346 m/s

and we know

velocity=frequency\times \lambda

v=f\times \lambda

346=f\times 0.25

f=1384 Hz

5 0
3 years ago
Read 2 more answers
A firefighter with a weight of 756 N slides down a vertical pole with an acceleration of 2.96 m/s2, directed downward. What are
Katen [24]

Answer:

a) F = 527.65 N, Force applied is upwards.

b)F = - 527.65 N, where, negative sign depicts Force is applied downwards.

Explanation:

Data provided:

Weight of the firefighter = 756 N

Mass of the firefighter = 756/9.8 = 77.14 Kg

Acceleration, a = 2.96 m/s²

a) In the absence of the pole the firefighter would have been moving down with an acceleration of 9.8 m/s (i.e the acceleration due to the gravity), but due to the presence of the pole the acceleration of the firefighter has been reduced. thus, a force is applied by the pole on the firefighter to reduce the acceleration.

therefore, we have

F = ma(net) = 77.14 × (9.8-2.96) = 527.65 N, Force applied is upwards.

B) According to the Newton's third law, the force will be equal and opposite to the force in the part a)

thus, we have

F = - 527.65 N

3 0
3 years ago
You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
spayn [35]

To solve this problem we will apply the concepts related to Reyleigh's criteria. Here the resolution of the eye is defined as 1.22 times the wavelength over the diameter of the eye. Mathematically this is,

\theta = \frac{1.22 \lambda }{D}

Here,

D is diameter of the eye

D = \frac{1.22 (539nm)}{5.11 mm}

D= 1.287*10^{-4}m

The angle that relates the distance between the lights and the distance to the lamp is given by,

Sin\theta = \frac{d}{L}

For small angle, sin\theta = \theta

sin \theta = \frac{d}{L}

Here,

d = Distance between lights

L = Distance from eye to lamp

For small angle sin \theta = \theta

Therefore,

L = \frac{d}{sin\theta}

L = \frac{0.691m}{1.287*10^{-4}}

L = 5367m

Therefore the distance is 5.367km.

4 0
3 years ago
Dark areas on the surface of the Sun that exhibit intense magnetic activity are
svp [43]
I think it's A) Sunspots. I hope this helps:)    
6 0
3 years ago
Read 2 more answers
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