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kodGreya [7K]
3 years ago
5

Compare positive and negative feedback mechanisms.

Physics
2 answers:
svlad2 [7]3 years ago
7 0

Positive feedback mechanisms is the types of feedback loop in which a change in a particular direction causes additional change in same direction. it is also called positive feedback loops or positive feedback systems.

Negative feedback mechanism tends to bring conditions within the body back to it's normal state. it is also called negative feedback loops or negative feedback systems.

<h2>Further Explanation</h2>

Positive feedback mechanisms are mostly used for variables that have the ability to amplify itself. Positive feedback can be very harmful in most cases, and can also contribute to normal function when used in limited fashion.  

An example of positive feedback occurs in lactation, in which a nursing mother produces breast milk for her infant. During pregnancy, the levels of the hormone (Prolactin) that stimulates milk production increases, but progesterone prevents milk production.

However, the progesterone levels will drop soon as a baby is born and the placenta is released from the uterus and this will cause the breast milk to flow. As the baby sucks the breast, the breast is also stimulated.

This stimulation causes further release of prolactin and more milk is produced. This positive feedback makes it possible for the baby to have enough milk during feeding.

Negative feedback mechanisms is a type of feedback loop in which a change in a direction causes changes in opposite direction.

For example, negative feedback loop that involves glucagon and insulin can help maintain a normal glucose level.

If the glucose is very high, the body discharges insulin into the bloodstream and if low, the body releases glucagon. The glucagon causes the release of glucose from the body cell.

LEARN MORE:

  • positive and negative feedback brainly.com/question/12299473

KEYWORDS:

  • positive feedback mechanisms
  • negative feedback mechanisms
  • hormones
  • glucose
  • feedback loops
NeX [460]3 years ago
6 0

Answer:

In positive feedback mechanism, the output is fed back to the system which further increases the output. Hence, it is known as positive feedback because it amplifies the output.

In the negative feedback mechanism, the output is fed back to the system which further decreases the the output. Hence, it is known as negative feedback because it reduces the output.

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Answer:

1650\:\mathrm{m}

Explanation:

We can use the following kinematics equations to solve this problem:

v_f=v_i+at,\\{v_f}^2={v_i}^2+2a\Delta x.

Using the first one to solve for acceleration:

132=88+a(15),\\15a=44,\\a=\frac{44}{15}=2.9\bar{3}\:\mathrm{m/s^2}.

Now we can use the second equation to solve for the distance travelled by the airplane:

132^2=88^2+2\cdot2.9\bar{3}\cdot \Delta x,\\\Delta x= \frac{9680}{2\cdot2.9\bar{3}},\\\Delta x =\fbox{$ 1650\:\mathrm{m}$}(three significant figures).

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3 years ago
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3 years ago
A person sitting on a pier observes incoming waves that have a sinusoidal form with a distance of 2.5 m between the crests. Of a
Doss [256]

Answer:

Part(a): The frequency is \bf{0.2~Hz}.

Part(b): The speed of the wave is \bf{0.5~m/s}.

Explanation:

Given:

The distance between the crests of the wave, d = 2.5~m.

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The distance between any two crests of a wave is known as the wavelength of the wave. So the wavelength of the wave is \lambda = 2.5~m.

Also, the time required for the wave for each laps is the time period of oscillation and it is given by T = 5.0~s.

Part(a):

The relation between the frequency and time period is given by

\nu = \dfrac{1}{T}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)

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Part(b):

The relation between the velocity of a wave to its frequency is given by

v = \nu \lambda~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(2)

Substituting the value of \nu and \lambda in equation (2), we have

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2 years ago
At 600.0 k the rate constant is 6.1× 10–8 s–1. what is the value of the rate constant at 785.0 k?
photoshop1234 [79]
Missing details. Complete text is:"The following reaction has an activation energy of 262 kJ/mol:
C4H8(g) --> 2C2h4(g)
At 600.0 K the rate constant is 6.1× 10–8 s–1. What is the value of the rate constant at 785.0 K?"
To solve the exercise, we can use Arrhenius equation:
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\ln( \frac{K_2}{K_1})=12.38
And using K_1=6.1\cdot 10^{-8} s^{-1} , we find K2:
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When I walked on stones in the Sinai Desert, the dry wind with a little bit of sand or dust in it built up enough static charge on me that I got a shock every time I stood less than a foot away from my partner.

I had the same experience a few years later near Ouarzazate in the interior of Morocco.

When you hear people say "the desert is dry", they mean it's <em>DRY !  </em>

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3 years ago
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