Atoms are attracted to each other because____
1 answer:
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The mass is missing. The mass of the elevator is 1650 kg.
Answer:
The tension in the cable is 19387.5 N.
Explanation:
Given:
Initial velocity of the elevator (u) = 0 m/s
Acceleration in the upward direction (a) = 1.95 m/s²
Time taken by the elevator (t) = 2.15 s
Mass of the elevator and persons (m) = 1650 kg
Let the tension in the cable wire be 'T' Newtons.
Now, there are 2 forces acting in the vertical direction. One is tension in the upward direction and the other the weight of the elevator in the downward direction.
As the elevator is accelerating upward, the net force acts in the upward direction.
So, net force on the elevator is given as:
Now, from Newton's second law, net force equals mass times acceleration.
Plug in the given values and solve for 'T'. This gives,
Therefore, the tension in the cable is 19387.5 N.
Newton's second law states that the product between the mass and the acceleration of an object is equal to the force applied:
from which we find an expression for the acceleration:
(1)
Both objects are moving by uniformly accelerated motion (because the force applied is constant), so we can also using the following relationship
(2)
where
is the final speed of the object
is the initial speed
S is the distance covered
By substituting (1) into (2), and by removing (since the final velocity of the two objects is zero), we find
where we can ignore the negative sign (because the force F will bring another negative sign).
For the first object, we have
![S= \frac{(2.0 m/s)^2 (4.0 kg)}{2F} = \frac{8}{F} [m]](https://tex.z-dn.net/?f=S%3D%20%5Cfrac%7B%282.0%20m%2Fs%29%5E2%20%284.0%20kg%29%7D%7B2F%7D%20%3D%20%20%5Cfrac%7B8%7D%7BF%7D%20%5Bm%5D%20)
And for the second object we have
![S= \frac{(4.0 m/s)^2 (1.0 kg)}{2F} = \frac{8}{F} [m]](https://tex.z-dn.net/?f=S%3D%20%5Cfrac%7B%284.0%20m%2Fs%29%5E2%20%281.0%20kg%29%7D%7B2F%7D%20%3D%20%5Cfrac%7B8%7D%7BF%7D%20%5Bm%5D%20)
And since the braking force applied to the two objects is the same, the two objects cover the same distance.
from which we find an expression for the acceleration:
Both objects are moving by uniformly accelerated motion (because the force applied is constant), so we can also using the following relationship
where
S is the distance covered
By substituting (1) into (2), and by removing
where we can ignore the negative sign (because the force F will bring another negative sign).
For the first object, we have
And for the second object we have
And since the braking force applied to the two objects is the same, the two objects cover the same distance.