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Triss [41]
3 years ago
14

Calculate the moment of inertia for a solid cylinder with a mass of 100g and a radius of 4.0 cm

Physics
2 answers:
Vladimir [108]3 years ago
5 0

Solution here,

mass of cylinder(m)=100 g

radius of cylinder(r)= 4 cm

momoent of inertia(I)=?

we have,

I=mr^2=100×4^2=1600 g/cm^2

yKpoI14uk [10]3 years ago
3 0

Answer:

The moment of inertia for the cylinder is 1600gcm².

Explanation:

In a cylinder with mass m, in g, and radius r, in cm, the moment of inertia is given, in gcm² by the following formula:

I = mr^{2}

In this problem, we have that:

solid cylinder with a mass of 100g and a radius of 4.0 cm. This means that m = 100, r = 4.

So

I = mr^{2} = 100*(4)^{2} = 1600

The moment of inertia for the cylinder is 1600gcm².

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Anettt [7]

Answer:

See the explanation below.

Explanation:

Solving the first image question:

C ) The resulting force is defined by Newton's second law which tells us that the sum of the forces on a body is equal to the product of mass by acceleration. That is, there must be a force that acts on a body to produce an acceleration. If there is no acceleration it is because there are no external forces or developed by the body. And if there is no acceleration the body moves at a constant speed, in a straight line, so the response is C.

For the second image, we must remember that weight is defined as the product of mass by gravitational acceleration.

W = m*g

where:

W = weight [N]

m = mass [kg]

g = gravity acceleration [m/s²]

Now we have

m = 50 [kg]

ge = Earth gravity acceleration = 10 [m/s²]

gp = Distant planet gravity acceleration = 4 [m/s²]

We = ge*m

We = 10*50 = 500 [N]

Wp =gp*m

Wp = 4*50 = 200 [N]

Therefore the answer is D

For the third image, The mass is always going to be preserved, regardless of where the body or object is in space, its weight is the only one that changes since the gravitational force is modified. That is, the mass on the moon and on Earth will always be the same.

m = 70 [kg]

First, we must calculate the acceleration, by means of the following equation of kinematics.

v_{f} =v_{o} +a*t

where:

Vf = final velocity = 20 [m/s]

Vo = initial velocity = 0 (because stars from the rest)

a = acceleration [m/s²]

t = time = 4 [s]

20 = 0 + a*4

20 = 4*a

a = 5 [m/s²]

Now using Newton's second law which tells us that the total force acting on a body is equal to the product of mass by acceleration.

F = m*a

where:

F = force [N] (units of Newtons)

m = mass = 2 [kg]

a = acceleration = 5 [m/s²]

F = 2*5

F = 10 [N]

The body of Figure D, since a total force of 25 [N] to the left acts on it, in the rest of cases the force is zero or much less than 25 [N]

50 + 40 - 35 - 30 = F

F = 25 [N]

8 0
2 years ago
If I push on the wall with 75 Newtons of force, the wall will push back with __
Scilla [17]

Answer: 0

Explanation:

75 newtons will push back canceling it out make it 0

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3 years ago
If i click on a mouse does that show energy transfer?
Radda [10]

Answer:

Yes

Explanation:

You are using energy to click the mouse, and the energy moves from your fingers to the mouse clicker.

8 0
2 years ago
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The light reactions of photosynthesis supply the calvin cycle with __________.
Margaret [11]

Answer:

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Explanation:

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2 years ago
24. An elevator is moving vertically up with an acceleration a. The force exerted on the floor by a passenger of mass m is
Wewaii [24]

<u>Given </u><u>:</u><u>-</u>

  • An elevator is moving vertically up with an acceleration a.

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u>

  • The force exerted on the floor by a passenger of mass m .

<u>Solution</u><u> </u><u>:</u><u>-</u>

As the man is in a accelerated frame that is <u>non </u><u>inertial</u><u> frame</u><u> </u>, we would have to think of a pseudo force .

  • The direction of this force is opposite to the direction of acceleration the frame and its magnitude is equal to the product of mass of the concerned body with the acceleration of the frame .

For the FBD refer to the attachment . From that ,

\implies Weight_{apparent}= mg + ma

<u>Hence</u><u> </u><u>option</u><u> </u><u>d </u><u>is </u><u>correct</u><u> </u><u>choice </u><u>.</u>

<em>I </em><em>hope</em><em> this</em><em> helps</em><em> </em><em>.</em>

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