The force constant of the spring is determined as 14,222.2 N/m.
<h3>Force constant of the spring</h3>
Apply the principle of conservation of energy,
K.E = U
where;
- K.E kinetic energy of the elevator
- U is elastic potential energy of the spring
¹/₂mv² = ¹/₂kx²
mv² = kx²
k = mv²/x²
Where;
- m is mass of the elevator
- v is speed
- x is compression of the spring
k = (2000 x 8²)/(3²)
k = 14,222.2 N/m
Thus, the force constant of the spring is determined as 14,222.2 N/m.
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Answer:
Hello the diagram related to your question is attached below
answer: a) 851 m/s
b) 8506.1 secs
Explanation:
calculate the periodic time of the satellite using the equation below
t =
-- ( 1 )
where ; R = 6370 km
h = 500 km
g = 9.81 m/s^2
input given values into equation 1
t = 5670.75 secs
next calculate the periodic time taken by the space craft
<u>a) determine the increase in speed </u>
V = v -
where ; v = 8463 m/s , R = 6370 km, h = 500 km
V = 851 m/s
b) Determine the periodic time for the elliptic orbit
τ = 
=
= 8506.1 secs
attached below is the remaining part of the detailed solution
1 to 5 would be your answer
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