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zalisa [80]
3 years ago
8

Imagine Two Artificial Satellites Orbiting Earth At The Same Distance. One Satellite Has A Greater Mass Than The Other One? Whic

h Of The Following Would Be True About Their Motion?A.The satellite with the greater mass is being pulled toward Earth w/ less of a force than the other satelliteB.The satellite w/ the greater mass is being pulled toward Earth w/ a greater force than the otherC.The two satellites are being pulled equal force by the moonD.The two satellites are being pulled toward Earth w/ equal forceImagine Two Artificial Satellites w/ Equal Masses Orbiting Earth. One Satellite Is Orbiting Closer To Earth Than The Other Satellite. Which Of The Following Would Be True About Their Motions?A.The satellite closer to Earth will be pulled toward Earth w/ the same gravitational pull as the other satellite B.The satellite closer to Earth will be pulled toward Earth w/ less gravitational pull than the other satellite C.Both satellites will be pulled w/ equal force toward the moonD.The satellite closer to Earth will be pulled toward Earth w/ more gravitational pull than the other satelliteHow Will Resistance Change When The Voltage Increases In A Electric Circuit If The Current Remains Constant?A.It will decrease B.It will stay the sameC.It will increase D.It will decrease,then increase 
Physics
1 answer:
Bad White [126]3 years ago
6 0

After reading this whole question, I feel like I've already
earned 5 points !

-- Two satellites at the same distance, different masses:

The forces of gravity between two objects are directly
proportional to the product of the objects' masses.  In
other words, the gravitational forces between the Earth
and an object on its surface are proportional to the mass of
the object.  In other words, people with more mass weigh more
on the Earth, and the Earth weighs more on them. 

If the satellites are both at the same distance from Earth,
then the Earth pulls on the one with more mass with greater
force, and also the one with more mass pulls on the Earth
with greater force.

-- Two satellites with the same mass, at different distances:

The forces of gravity between two objects are inversely
proportional to the square of the distance between them. 
In other words, the gravitational forces between the Earth
and an object are inversely proportional to the square of
the distance between the object and the center of the Earth. 

If the satellites both have the same mass, then the Earth
pulls on the nearer one with greater force, and also the
nearer one pulls on the Earth with greater force.

-- Resistor in a circuit when the voltage changes:

The resistance depends on how the resistor was manufactured. 
Its resistance is marked on it, and doesn't change.  It remains
the same whether the voltage changes, the current changes,
the time of day changes, the cost of oil changes, etc.

If you increase the voltage in the circuit where that resistor is
installed, the current through the resistor increases.  If the current
remains constant, then you can be sure that somebody snuck over
to your circuit when you weren't looking, and they either installed
another resistor in series with the original one to make the total
resistance bigger, or else they snipped the original one out of the
circuit and quickly connected one with more resistance in its place.

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Assume the earth to be a nonrotating sphere with mass MEME and radius RERE. If an astronaut weights WW on the ground, what is hi
Solnce55 [7]

Answer:

The weight at a distance 2 RE from surface of earth is <em>W/9</em>

Explanation:

For the value of acceleration due to gravity (g), we have a formula, that is:

g = (G)(ME)/(RE)²    ----- equation (1)

where,

G = Gravitational Constant

ME = Mass of Earth

RE = Radius of Earth

g = Acceleration due to gravity on surface of earth = 9.8 ms²

When the person goes 2RE, distance above earth's surface. Then the total distance from center of earth becomes: 2RE + RE = 3RE.

Therefore, equation (1) becomes:

gh = (G)(ME)/(3RE)²

where,

gh = acceleration due to gravity at height

gh = (G)(ME)/(RE)²9

using equation (1), we get:

gh = g/9

Now, he weight is given by formula:

W = mg   ------- equation (2)

At height 2RE

Wh = (m)(gh)

where,

Wh = Weight at height = ?

m = mass of astronaut

Therefore, using vale of gh, we get:

Wh = mg/9

Using equation (2), we get:

<u>Wh = W/9</u>

6 0
3 years ago
If the average distance between bumps on a road is about 10 m and the natural frequency of the suspension system in the car is a
Mnenie [13.5K]
When you hit a bump every 0.9 seconds.
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List at least 3 ways for you to represent your data graphically
yawa3891 [41]
1. circle graph
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hope this helps
6 0
1 year ago
Read 2 more answers
PLEASE HELP!
Kobotan [32]

Answer:

No

Explanation:

Cause a monster truck don

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If the wagon travels 18.75 m, what is the work done on the wagon
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If the wagon travels 18.75 m, then the work done on the wagon is

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The unit is Joules .


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