Answer:
Inertia relates directly to an object's <em>mass</em>. It is its inherent property and expresses how much force is needed to bring the object to a certain level of acceleration. It is the sole factor.
Momentum relates proportionally to two factors: <em>mass</em> and <em>velocity</em>. As such, momentum is not an inherent property of an object but a measure dependent on it current velocity, in addition to its mass.
The structure and curvature of the Earth results in beams of sunlight glancing off the equator and reaching other areas of the Earth. This means that the areas at the equator receive more energy as sun's rays hit them directly.
Therefore, the answer is C.
It is true that the light is 15.000 more dangerous than the radiation of a microwave.
<h3>What is the wavelength?</h3>
The wavelength shows the extent or how far the wave travels. Now we know that the energy of the wave can be use to find out how much dangerous the wave is.
Now;
1.6 * 10^-19 J = 1eV
x J = 1.8 eV
x = 1.8 eV * 1.6 * 10^-19 J /1eV
x = 2.88 * 10^-19 J
Now if the energy of the microwaves is 1.2 x 10^-4 J, then it follows that;
2.88 * 10^-19 J/ 1.2 x 10^-4 J,
= 2.4 * 10^15
Hence, it is true that the light is 15.000 more dangerous than the radiation of a microwave.
Learn more about microwave:brainly.com/question/15708046
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Answer:
a) The final pressure is 1.68 atm.
b) The work done by the gas is 305.3 J.
Explanation:
a) The final pressure of an isothermal expansion is given by:

Where:
: is the initial pressure = 5.79 atm
: is the final pressure =?
: is the initial volume = 420 cm³
: is the final volume = 1450 cm³
n: is the number of moles of the gas
R: is the gas constant
Hence, the final pressure is 1.68 atm.
b) The work done by the isothermal expansion is:

Therefore, the work done by the gas is 305.3 J.
I hope it helps you!