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SIZIF [17.4K]
3 years ago
5

What is the value of x^3*y^1 when x=5 and y=10

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
8 0

Answer:

1250

Step-by-step explanation:

x^3*y^1

Let x = 5 and y = 10

5^3* 10^1

PEMDAS says powers first

125 * 10

Then multiply

1250

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Jacob and 6 of his friends went out to eat. They decided to split the bill evenly. Each person paid $14.93. What was the total b
jasenka [17]

Answer:

$104.51

Step-by-step explanation:

No.of people = 7

How much each person paid = $14.93

How much is the total bill = $14.93 x 7

                                          = $104.51

<em>I was bored so I added the steps lol</em>

8 0
2 years ago
Read 2 more answers
Graph the first six terms of a sequence where a1=5 and r=1.25
emmainna [20.7K]
The sequence above is geometric progression. 
The nth term of such sequence is given by;

Tn = ar∧(n-1),
Where a⇒first term and
            r⇒common ratio

So, 1st term = 5×1.25∧(1-1) = 5×1.25∧0 =5 
      2nd term = 5×1.25∧(2-1) = 5×1.25 = 6.25
      3rd term = 5×1.25∧(3-1) = 5×1.25² = 7.8125
       4th term = 5×1.25∧(4-1) =5×1.25³ = 9.765625
       5th term = 5×1.25∧(5-1) = 5×1.25∧4 = 12.20703125
       6th term = 5×1.25∧(6-1) = 5×1.25∧5 = 15.25878909
7 0
3 years ago
I need help with this
12345 [234]
Are you solving for x and y? 5y + 2(6x) would just be 5y + 12x
6 0
3 years ago
Find 4 more than the quotient of 9 and 2
fenix001 [56]
Im not sure but it should be 8.5
7 0
3 years ago
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The derivative of (x^2 +1)(x^3+ 1) (by definition and basic rule)
dlinn [17]

Answer:

f'(x) = 5x^4 + 2x + 3x^2

Step-by-step explanation:

To find the derivative of this equation we can do two things.

One method is to use the product rule, which states that when f(x) consists of two functions multiplied to each other (meaning f(x) = g(x) * h(x)), the derivative is f'(x) = g'(x)*h(x) + g(x)*h'(x). In simple language, the derivative is found by finding the derivative of x² + 1 and multiplying it with the normal function of x³ + 1, after which you add the product of the nnormal function of x² + 1 and the derivative of x³ + 1.

it might be clearer when I show you:

f(x) = (x^2 + 1)(x^3 + 1)\\f'(x) = (2x)(x^3 + 1) + (x^2 + 1)(3x^2)\\Simplify:\\f'(x) = 2x^4 + 2x + 3x^4 + 3x^2 = 5x^4 + 3x^2 + 2x\\

If you are not familiar with this rule you can first write out the function and then use the basic rule:

f(x) = (x^2 +1)(x^3+1) = x^5 + x^2 + x^3 + 1\\f'(x) = 5x^4 + 2x + 3x^2

If you need any further help please say so in the comments! I hope this helps! If the steps seem complicated, I suggest you could revise expanding brackets (the first step of the second method) and the basic rules of deriving, but feel free to reach out if you struggle afterwards still

8 0
2 years ago
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