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andrey2020 [161]
3 years ago
15

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the rectangles formed by the sets of points

to their corresponding areas.
A(-9,8), B(-5,5), C(1,13), D(-3,16)

E(30,20), F(39,29), G(49,19), H(40,10)

I(-6,2), J(2,2), K(2,-8), L(-6,-8)

M(5,5), N(11,5), O(11,-5), P(5,-5)

Q(10,0), R(15,5), S(25,-5), T(20,-10)

U(0,5), V(15,20), W(25,10),X(10,-5)

50 square units

300 square units

100 square units

80 square units

Mathematics
2 answers:
tigry1 [53]3 years ago
6 0

IJKL=80 square units

QRST =100 square units

UVWX =300 square units

ABCD =50 square units

you are welcome!!!

lana [24]3 years ago
3 0

Answer:

Area of a rectangle = length × width

= Product of two adjacent sides

By the distance formula,

The length of a line segment having end points (x_1,y_1) and (x_2,y_2),

=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\text{ unit}

The area of rectangle having vertices A(-9,8), B(-5,5), C(1,13), D(-3,16),

= AB × BC  

= √25 × √100          

= 5 × 10          

= 50 square unit,

The area of rectangle having vertices E(30,20), F(39,29), G(49,19), H(40,10)

= EF × FG

= √162 × √200  

= 81√2 × 10√2

= 1620 square unit,

The area of rectangle having vertices I(-6,2), J(2,2), K(2,-8), L(-6,-8)

= IJ × JK

= √64 × √100      

= 8 × 10

= 80 square unit,

The area of rectangle having vertices M(5,5), N(11,5), O(11,-5), P(5,-5)

= MN × NO

= √36 × √100    

= 6 × 10

= 60 square unit,

The area of rectangle having vertices U(0,5), V(15,20), W(25,10),X(10,-5)

= UV × VW

= √450 × √200  

= 300 square unit,

Area of rectangles having vertices Q(10,0), R(15,5), S(25,-5), T(20,-10)

= QR × RS

= √50 × √200    

= 5√2 ×10√2

= 100 square unit.

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