In pure translation or in roll without slip?
In pure translation, just use Fnet = m*a. Fnet = 7.5 Newtons
In roll without slip it has effectively more inertia than 5 kilograms. The effective inertia can be found as:
m_effective = m + I/r^2
For a uniform solid sphere, I = 2/5*m*r^2
So m_effective = 7/5*m
To make a 5 kg bowling ball accelerate at 1.5 m/s^2 in roll without slip, it requires Fnet = 10.5 Newtons, and this ASSUMES that all forces causing the net force on it have lines of action through its center of mass (most common case).
i hope this is what ur looking for
The third choice is correct and can be found by plugging the values into Point-Slope Form.
3/5 = 72/x
First u need to cross multiply
5*72 = 360
Now divide
360/3 =120. <<< that's x
So
3/5 = 72/120 < answer
First let's find the angles a and b.
We have then:
sin a = 4/5
a = Asin (4/5)
a = 53.13 degrees.
cos b = 5/13
b = Acos5 / 13
b = 67.38 degrees.
We now calculate cos (a + b). To do this, we replace the previously found values:
cos ((53.13) + (67.38)) = - 0.507688738
Answer:
-0.507688738
Note: there is another way to solve the problem using trigonometric identities.
