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3 years ago

Gases are highly compressible due to

Chemistry

2 answers:

almond37 [142]3 years ago

4 0

Answer:

Gases are compressible because most of the volume of a gas is composed of the large amounts of empty space between the gas particles.

Explanation:

If we put pressure on a solid or a liquid, there is essentially no change in volume. The atoms, ions, or molecules that make up the solid or liquid are very close together.

nexus9112 [7]3 years ago

3 0

Answer:

I don't really understand what you asking in this question so if you don't mind plz tell me in a better form

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An ideal gas is brought through an isothermal compression process. The 3.00 mol of gas goes from an initial volume of 261.6×10−6

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Answer : The temperature and the final pressure of the gas is, 586.83 K and $1.046\times 10^{9}atm$ respectively.

Explanation : Given,

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Final volume of the gas = $138.2\times 10^{-6}m^3$

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First we have to calculate the temperature of the gas.

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As per first law of thermodynamic,

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where,

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So, at constant temperature the internal energy is equal to zero.

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$w=nRT\ln (\frac{V_2}{V_1})$

where,

w = work done = 9340 J

n = number of moles of gas = 3 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas = ?

$V_1$ = initial volume of gas

$V_2$ = final volume of gas

Now put all the given values in the above formula, we get the temperature of the gas.

$9340J=3mole\times 8.314J/moleK\times T\times \ln (\frac{261.6\times 10^{-6}m^3}{138.2\times 10^{-6}m^3})$

$T=586.83K$

Now we have to calculate the final pressure of the gas by using ideal gas equation.

$PV=nRT$

where,

P = final pressure of gas = ?

V = final volume of gas = $138.2\times 10^{-6}m^3=138.2\times 10^{-9}L$

T = temperature of gas = 586.83 K

n = number of moles of gas = 3 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get:

$P\times (138.2\times 10^{-9}L)=3mole\times (0.0821L.atm/mole.K)\times (586.83K)$

$P=1.046\times 10^{9}atm$

Therefore, the temperature and the final pressure of the gas is, 586.83 K and $1.046\times 10^{9}atm$ respectively.

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