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Oksi-84 [34.3K]
3 years ago
14

What is the concentration of an hbr solution if 12.0 ml of the solution is neutralized by 15.0 ml of a 0.25 m koh solution?

Chemistry
1 answer:
Snowcat [4.5K]3 years ago
4 0
The balanced equation for the reaction between KOH and HBr is as follows;
KOH + HBr --> KBr + H₂O
stoichiometry of KOH to HBr is 1:1
number of KOH moles reacted - 0.25 mol/L x 0.015 L = 0.00375 mol
according to molar ration 
number of KOH moles reacted = number of HBr moles reacted 
number of HBr moles reacted - 0.00375 mol 
if 12 mL of HBr contains - 0.00375 mol 
then 1000 mL of HBr contains - 0.00375 mol / 12 mL x 1000 mL = 0.313 mol
therefore molarity of HBr is 0.313 M
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3 years ago
Given the following equation: 2 K + Cl2 ---> 2 KCl
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Answer:

2 moles of KCl will be produced

Explanation:

Given parameters:

Number of moles of K = 2 moles

Unknown:

Number of moles of KCl produced  = ?

Solution:

To solve this problem;

Obtain a balanced chemical equation:

           2K +  Cl₂   →   2KCl ;

Since K is the limiting reactant, its amount will determine the extent of this reaction.

   From the balanced equation;

           2 moles of K will produce 2 moles of KCl

        Given that 2 moles of K reacted, 2 moles of KCl will be produced

5 0
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The atmospheric pressure in Denver, Colorado, is usually about 84.00 kPa. What is this pressure in atm and torr units?
tresset_1 [31]

Answer:

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<u>84.00 kPa = 0.831683168 atm</u>

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How does the energy of an electron change when the electron moves closer to the nucleus
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8 0
3 years ago
Iodine-131 is a beta emitter used as a tracer in radio immunoassays in biological systems. It follows first order kinetics. The
allsm [11]

<u>Answer:</u> The amount of Iodine-131 remain after 39 days is 0.278 grams

<u>Explanation:</u>

The equation used to calculate rate constant from given half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life of the reaction = 8.04 days

Putting values in above equation, we get:

k=\frac{0.693}{8.04days}=0.0862days^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant = 0.0862days^{-1}

t = time taken for decay process = 39 days

[A_o] = initial amount of the sample = 8.0 grams

[A] = amount left after decay process = ?

Putting values in above equation, we get:

0.0862=\frac{2.303}{39}\log\frac{8.0}{[A]}

[A]=0.278g

Hence, the amount of Iodine-131 remain after 39 days is 0.278 grams

3 0
2 years ago
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