4. Solve the following heat flow problem, being sure to show all your work (you may either type your

Chemistry

1 answer:

Viktor [21]4 years ago

5 0

Answer:

0.70 J/g.°C

Explanation:

Step 1: Given data

Mass of graphite (m): 402 g

Heat absorbed (Q): 1136 J

Initial temperature: 26°C

Final temperature: 30 °C

Specific heat of graphite (c): ?

Step 2: Calculate the specific heat of graphite

We will use the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 1136 J / 402 g × (30°C - 26°C)

c = 0.70 J/g.°C

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Calculate the molecular mass of Co(NO3)2<br>with steps please

Nana76 [90]

Answer:

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Explanation:

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2 years ago

During an experiment, 321.1 grams of strontium phosphite are measured into a beaker. How many moles of strontium phosphite are i

Allushta [10]

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It is known that 1 mole of any substance is equal to the molar mass of that substance. So for the case of strontium phosphite, the molar mass is found to be 420.8 g/mol.

This means 1 mole of Strontium phosphite will contain 420.8 g of strontium phosphite.

Then 1 g of strontium phosphite will have $\frac{1}{420.8}$ moles of strontium phosphite.