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Alchen [17]
3 years ago
12

One cooy machine can run off copies in 198 minutes. A newer machine can do the same job in 126 minutes. How long does it take th

e two​ machines, working​ together, to make all of the necessary​ copies?
Mathematics
1 answer:
yanalaym [24]3 years ago
4 0
This depends on the necessary number of copies.
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What is the mass of 2.5 moles of carbon dioxide?
GarryVolchara [31]

Answer:

110 grams

Step-by-step explanation:

CO2 molecule is made up of Carbon (atomic mass =12) and oxygen (atomic mass=16).

So first finding the mass of 1 molecule of CO2 which is equals to

= mass of 1 carbon atom + masses of 2 oxygen atom, we get

= 12+(16*2)= 12+32= 44 a.m.u.

Now 1 molecule of CO2 has mass 44 amu so mass of 1 mole CO2 will be 44 grams.( 1 a.m.u.=1.6729*10^-33 grams. 1 mole = 6.022*10^23, so 44 a.m.u.=73.6076*10^-33 grams approx. For one mole CO2, 73.6076*10^-33*6.022*10^23 which is approximately equals to 44 grams. )

1 mole CO2= 44grams, so 2.5 moles = 44*2.5= 110 grams

So our answer is 110 grams.

lowkey hope this helped you, good luck whatever you need it for Imaooo

3 0
2 years ago
Help please...........bad
djverab [1.8K]

Answer: 0,5, and -4 is the zeros

Step-by-step explanation:

3 0
2 years ago
Which set of points are collinear in the figure below?
lina2011 [118]

Answer:

zono eatas

Step-by-step explanation:

elledre de como dezie puaron

4 0
3 years ago
PLEASE HURRY~ CHOOSING BRAINLIEST
svp [43]

Answer:

Step-by-step explanation:

Because the y intercept is two our y=mx+b equation looks like this

y=mx+2

We then need to find a slope that gives us an x intercept of 3 or satisfies the coordinates of (3,0)

We can plug this in and solve

0=3m+2

-2=3m

-2/3=m

which means our final equation is

-2/3x+2

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6 0
2 years ago
Read 2 more answers
Derek walks along a road which can be modeled by the equation y =2x, where (0,0) represents his starting point. When he reaches
Lady_Fox [76]

Answer:

(35,0)

Step-by-step explanation:

Consider the diagram below, the starting point is given as A and the finish point given as C.

Using similar right-angle triangle, we have that:

\frac{|AM|}{|BM|}= \frac{|BM|}{|MC|}\\\frac{7}{14}= \frac{14}{x}\\7x=14 X 14\\x=196/7=28

Therefore to find the point where Derek stops at C, we first determine the distance |AC|

|AC|=7+28=35

The Coordinates at C where Derek stops is (35,0)

8 0
3 years ago
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