3 years ago

Which is the center of a circle whose equation is x2+y2+4x-8y+11=0?

Mathematics

1 answer:

Nikolay [14]3 years ago

6 0

Answer:

Center (-2 , 4)

Step-by-step explanation:

x^2 + 4x + y^2 - 8y = - 11

(x^2 + 4x + (4/2)^2 + (y^2 - 8y + (8/2)^2 ) = - 11 + 4 + 16

(x + 2)^2 + (y - 4)^2 = 9

Center (-2, 4)

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