When Cr dissolves in 1 M H₂Cr₂O₇
Cr(s) ⇄ Cr³⁺ + 3 e⁻
Cr₂O₇²⁻ + 14 H⁺ + 6 e⁻ ⇄ 2 Cr³⁺ + 7 H₂O
by multiplying the first equation by 2 and add the 2 equations;
The balanced redox reaction will be:
2 Cr(s) + Cr₂O₇²⁻(aq) + 14 H⁺(aq) → 4 Cr³⁺(aq) + 7 H₂O(l)
From the balanced redox equation of the reaction, the coefficient of OH⁻ is 8.
<h3>What is the balanced redox equation of the reaction?</h3>
A redox equation is the equation of a redox reaction in which oxidation and reduction occurs simultaneously.
The given redox reaction takes place in a basic solution
The balanced redox equation of the reaction is given below:
4 H₂O(l) + 3 S²⁻(aq) + 2 NO₃⁻(aq) ---> 3 S(s) + 2 NO + 8 OH⁻(aq)
In conclusion, a redox equation is balanced when oxidation and reduction occur to the same extent.
Learn more about redox equations at: brainly.com/question/26750732
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The H+ in a solution that has a Ph of 8.73 is calculate as follows
Ph is always = - log (H+)
H+ = 10^-Ph
H+ is therefore = 10 ^- 8.73
H+ = 1.86 x10^-9 M
