Based on the ion structure, which of the following elements would form a bond with calcium in a one to one ratio and why?

When an oxygen atom is attached to a carbon atom the carbon atom becomes more?

Ad libitum [116K]

When an oxygen atom is attached to a carbon atom, the carbon atom becomes reduced.

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3 years ago

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which of the following features provides evidence of a glacier and establishes its directed of movement?

mariarad [96]

Answer:

The pressure from the weight of the glacier generates a layer of water that helps the ice glacier move downslope. This process is called basal sliding. Also, the glacier begins to move under its own weight. The glacier is so heavy and exerts so much pressure that the firn and snow melt without any increase in temperature.

5 0

3 years ago

An unknown gas effuses at one half the speed of oxygen. What is the molar mass of the unknown? It is either HBr or HI. Which gas

sertanlavr [38]

Answer:

HI.

Explanation:

Thomas Graham found that, at a constant temperature and pressure the rates of effusion of various gases are inversely proportional to the square root of their masses.

Rate of effusion ∝ 1/√molar mass.

(Rate of effusion of O₂) / (Rate of effusion of unknown gas) = (√molar mass of unknown gas) / (√molar mass of O₂).

An unknown gas effuses at one half the speed of that of oxygen.

∵ Rate of effusion of unknown gas = 1/2 (Rate of effusion of O₂)

∴ (Rate of effusion of O₂) / (Rate of effusion of unknown gas) = 2.

Molar mass of O₂ = 32.0 g/mol.

∵ (Rate of effusion of O₂) / (Rate of effusion of unknown gas) = (√molar mass of unknown gas) / (√molar mass of O₂).

∴ 2.0 = (√molar mass of unknown gas) / √32.0.

( √molar mass of unknown gas) = 2.0 x √32.0

By squaring the both sides:

∴ molar mass of unknown gas = (2.0 x √32.0)² = 128 g/mol.

∴ The molar mass of sulfur dioxide = 80.91 g/mol and the molar mass of HI = 127.911 g/mol.

So, the unknown gas is HI.

5 0

3 years ago

2. How have fossils been preserved over millions of years?

just olya [345]

Answer:A fossil is the remains or traces of a once-living plant or animal that was preserved in rock or other material before the beginning of recorded history. ... Fossils of single-celled organisms have been recovered from rocks as old as 3.5 billion years. Animal fossils first appear in rocks dating back about 1 billion years.

Explanation:

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3 years ago

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[H3O+] [OH−] pH Acidic or Basic 3.5×10−3 _____ _____ _____ _____ 3.8×10−7 _____ _____ 1.8×10−9 _____ _____ _____ _____ _____ 7.1

ankoles [38]

Answer:

See explanation below

Explanation:

I'm assuming this is a table you need to complete, so, you are not putting this in order, but I already found it in another place. let's do a little summary of the expressions we need to use in order to complete the chart.

To calculate pH we need the following expression:

pH = -log[H3O+] (1)

From this expression we can solve for [H3O+] in case we need it:

[H3O+] = 10^(-pH) (2)

When we have [OH-] we calculate the pOH and from there, the pH:

pOH = -log[OH-] (3)

and [OH-]:

[OH-] = 10^(-pOH) (4)

Finally to get the pH from pOH:

14 = pH + pOH

pH = 14 - pOH (5)

With these 5 expressions we can complete the chart. In picture 1, you have the actual chart.

To know if it's acidic or basic, that depends on the value of pH.

If pH <7 it's acidic

If pH >7 it's basic

If pH = 7 it's neutral

First case:

[H3O+] = 3.5x10^-3

pH = -log(3.5x10^-3) = 2.46 (acidic)

pOH = 14 - 2.46 = 11.54

[OH-] = 10^(-11.54) = 2.88x10^-12 M

Second case:

pOH = -log(3.8x10^-7) = 6.42

pH = 14 - 6.42 = 7.58 (it's basic)

[H3O+] = 10^(-7.58) = 2.63x10^-8 M

Third case:

pH = -log(1.8x10^-9) = 8.74 (it's basic)

pOH = 14 - 8.74 = 5.26

[OH-] = 10^(-5.26) = 5.5x10^-6 M

Fourth case:

[H3O+] = 10^(-7.15) =7.08x10^-8 M (Basic)

pOH = 14 - 7.15 = 6.85

[OH-] = 10^(-6.85) = 1.41x10^-7 M

Hope this can help you

7 0

3 years ago