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Let the 8% solution be A, the 20% solution be B and the final solution be C.
C = A + B
C = 12 + B
0.16C = 0.08(12) + 0.2(B)
0.16(12 + B) = 0.96 + 0.2B
0.96 = 0.04B
B = 24 Liters
C = 12 + 24
C = 36 Liters
Answer:
Explanation is in the answer
Explanation:
The pH of the buffer solution does not change appreciably because the strong acid (free H⁺) reacts with conjugate base of buffer producing more weak acid. pH formula of buffers is (Henderson-Hasselbalch formula):
pH = pKa + log ( [A⁻] / [HA] )
The addition of strong acid decreases [A⁻] increasing [HA]. pH change just in the log of the ratio of [A⁻] with [HA], that is a real little effect over pH of the buffer solution.
<span>Yes, mass is conserved. When sodium hydroxide (clear solution) and copper sulfate (blue solution) are mixed, they form a copper hydroxide (a blue solid) and sodium sulfate (a clear solution).
This can be tested simply. First weigh the masses (10 g and 57 g, which totals 67 g)) of the two starting solutions prior to mixing. Then mix and allow the reaction to occur and weigh the mass of the mixture (10g + 57 g = 67 g). The two solutions should have the same mass and therefore demonstrate conservation of mass.</span>