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valentinak56 [21]
3 years ago
9

Please help asap 25 pts

Mathematics
2 answers:
neonofarm [45]3 years ago
5 0

Answer:

y = 1/4 x

Step-by-step explanation:

GarryVolchara [31]3 years ago
4 0

y = 1/4 x because with the y-intercept being zero you don't have to show the integer 0 in the equation.

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Please help me on this !!
aev [14]

Answer:

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Step-by-step explanation:

srry but can't jelp

6 0
3 years ago
what are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotensue is 15 units long?
givi [52]
Refer to the diagram shown below.

Given:
m∠A = 19°
c = 15

By definition,
sin A = a/c
Therefore
a = c*sin A = 15*sin(19°) = 4.8835

cos A = b/c
Therefore
b = c*cos A = 15*cos(19°) =14.1828

Answer:
The lengths are 4.88, 14.18, and 15.00  (nearest hundredth)  

6 0
3 years ago
I will give you 5 stars and a heart!
Artemon [7]
So from these given details will be right choice A. sure because given that 1 unit cube = 1 inch so from this result that 48 unit cubes = 48 cubic inches 

hope this will help you 
7 0
3 years ago
Write the equation of the line that passes through (2, 4) and has a slope of –1 in point-slope form.
klemol [59]
Point slope form is just a point and the slope written in the form y-y1 =m (x-x1).
Where x1 and y1 (should be subscripts) are (x1,y1) the point you are given.
So in this case all you must do is plug in the given values:

( y-y1 ) = m ( x-x1 )
( y-4. ) = -1 ( x-2 )
This being your answer

I hope this helps!!
5 0
3 years ago
Read 2 more answers
What is the surface area of this design? 5 in 5 in 6.4 in 5 in 9 in
xeze [42]

ANSWER

197 {in}^{2}

EXPLANATION

The area of the two tra-pezoidal faces

= 2 \times  \frac{1}{2}  \times (9 + 5) \times 5 = 70 {in}^{2}

The area of the 5 by 6.4 rectangular face

= 6.4 \times 5 = 32  {in}^{2}

The area of the two square faces

= 2(5 \times 5) = 50 {in}^{2}

The area of the 9 by 5 rectangular face is

= 9 \times 5 = 45 {in}^{2}

The surface area of the design is:

70 + 32 + 50  + 45=197 {in}^{2}

6 0
3 years ago
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